reverse_iterator::operator*
Devuelve el elemento las direcciones de un que reverse_iterator.
reference operator*( ) const;
Valor devuelto
el valor de los elementos dirigidos por el reverse_iterator.
Comentarios
el operador devuelve * (actual – 1).
Ejemplo
// reverse_iterator_op_ref.cpp
// compile with: /EHsc
#include <iterator>
#include <algorithm>
#include <vector>
#include <iostream>
int main( )
{
using namespace std;
int i;
vector<int> vec;
for (i = 1 ; i < 6 ; ++i )
{
vec.push_back ( 2 * i );
}
vector <int>::iterator vIter;
cout << "The vector vec is: ( ";
for ( vIter = vec.begin ( ) ; vIter != vec.end ( ); vIter++ )
cout << *vIter << " ";
cout << ")." << endl;
vector <int>::reverse_iterator rvIter;
cout << "The vector vec reversed is: ( ";
for ( rvIter = vec.rbegin( ) ; rvIter != vec.rend( ); rvIter++)
cout << *rvIter << " ";
cout << ")." << endl;
vector <int>::iterator pos, bpos;
pos = find ( vec.begin ( ), vec.end ( ), 6 );
// Declare a difference type for a parameter
// declare a reference return type
reverse_iterator<vector<int>::iterator>::reference refpos = *pos;
cout << "The iterator pos points to: " << refpos << "." << endl;
}
Output
The vector vec is: ( 2 4 6 8 10 ).
The vector vec reversed is: ( 10 8 6 4 2 ).
The iterator pos points to: 6.
Requisitos
encabezado: <iterador>
espacio de nombres: std