Class.PackageName Property
Definition
Important
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Returns the fully qualified package name.
public string PackageName { [Android.Runtime.Register("getPackageName", "()Ljava/lang/String;", "", ApiSince=31)] get; }[<get: Android.Runtime.Register("getPackageName", "()Ljava/lang/String;", "", ApiSince=31)>]
member this.PackageName : stringProperty Value
the fully qualified package name
- Attributes
Remarks
Returns the fully qualified package name.
If this class is a top level class, then this method returns the fully qualified name of the package that the class is a member of, or the empty string if the class is in an unnamed package.
If this class is a member class, then this method is equivalent to invoking getPackageName() on the #getEnclosingClass enclosing class.
If this class is a #isLocalClass local class or an #isAnonymousClass() anonymous class, then this method is equivalent to invoking getPackageName() on the #getDeclaringClass declaring class of the #getEnclosingMethod enclosing method or #getEnclosingConstructor enclosing constructor.
If this class represents an array type then this method returns the package name of the element type. If this class represents a primitive type or void then the package name "java.lang" is returned.
Added in 9.
Java documentation for java.lang.Class.getPackageName().
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