FontDialog.ShowColor Property

Definition

Gets or sets a value indicating whether the dialog box displays the color choice.

C#
public bool ShowColor { get; set; }

Property Value

true if the dialog box displays the color choice; otherwise, false. The default value is false.

Examples

The following code example uses ShowDialog to display a FontDialog. This code requires that a Form has already been created with a TextBox and button placed on it. It also requires that the fontDialog1 has been created. The Font contains the size information but not the color information.

C#
private void button1_Click(object sender, System.EventArgs e)
 {
    fontDialog1.ShowColor = true;

    fontDialog1.Font = textBox1.Font;
    fontDialog1.Color = textBox1.ForeColor;

    if(fontDialog1.ShowDialog() != DialogResult.Cancel )
    {
       textBox1.Font = fontDialog1.Font ;
       textBox1.ForeColor = fontDialog1.Color;
    }
 }

Applies to

Produit Versions
.NET Framework 1.1, 2.0, 3.0, 3.5, 4.0, 4.5, 4.5.1, 4.5.2, 4.6, 4.6.1, 4.6.2, 4.7, 4.7.1, 4.7.2, 4.8, 4.8.1
Windows Desktop 3.0, 3.1, 5, 6, 7, 8, 9

See also