Point4D.Subtraction(Point4D, Point4D) Operator
Definition
Important
Some information relates to prerelease product that may be substantially modified before it’s released. Microsoft makes no warranties, express or implied, with respect to the information provided here.
public:
static System::Windows::Media::Media3D::Point4D operator -(System::Windows::Media::Media3D::Point4D point1, System::Windows::Media::Media3D::Point4D point2);
public static System.Windows.Media.Media3D.Point4D operator - (System.Windows.Media.Media3D.Point4D point1, System.Windows.Media.Media3D.Point4D point2);
static member ( - ) : System.Windows.Media.Media3D.Point4D * System.Windows.Media.Media3D.Point4D -> System.Windows.Media.Media3D.Point4D
Public Shared Operator - (point1 As Point4D, point2 As Point4D) As Point4D
Parameters
Returns
Returns the difference between point1
and point2
.
Examples
The following example shows how to use the overloaded subtraction operator to subtract a Point4D structure from a Point4D structure.
// Subtracts a Point4D from a Point4D using the overloaded - operator.
// Returns a Point4D.
Point4D point1 = new Point4D(10, 5, 1, 4);
Point4D point2 = new Point4D(15, 40, 60, 75);
Point4D pointResult = new Point4D();
pointResult = point1 - point2;
// pointResult is equal to (-5, -35, -59, -71)
// Displaying Results
syntaxString = "pointResult = point1 - point2;";
resultType = "Point4D";
operationString = "Subtracting a Vector3D from a Point4D";
ShowResults(pointResult.ToString(), syntaxString, resultType, operationString);
' Subtracts a Point4D from a Point4D using the overloaded - operator.
' Returns a Point4D.
Dim point1 As New Point4D(10, 5, 1, 4)
Dim point2 As New Point4D(15, 40, 60, 75)
Dim pointResult As New Point4D()
pointResult = point1 - point2
' pointResult is equal to (-5, -35, -59, -71)
' Displaying Results
syntaxString = "pointResult = point1 - point2"
resultType = "Point4D"
operationString = "Subtracting a Vector3D from a Point4D"
ShowResults(pointResult.ToString(), syntaxString, resultType, operationString)
Applies to
See also
Collaborer avec nous sur GitHub
La source de ce contenu se trouve sur GitHub, où vous pouvez également créer et examiner les problèmes et les demandes de tirage. Pour plus d’informations, consultez notre guide du contributeur.