Constructeur ServerConnection (String, String, String)
Initializes a new instance of the ServerConnection class with the specified server instance and logon credentials.
Espace de noms : Microsoft.SqlServer.Management.Common
Assembly : Microsoft.SqlServer.ConnectionInfo (en Microsoft.SqlServer.ConnectionInfo.dll)
Syntaxe
'Déclaration
Public Sub New ( _
serverInstance As String, _
userName As String, _
password As String _
)
'Utilisation
Dim serverInstance As String
Dim userName As String
Dim password As String
Dim instance As New ServerConnection(serverInstance, _
userName, password)
public ServerConnection(
string serverInstance,
string userName,
string password
)
public:
ServerConnection(
String^ serverInstance,
String^ userName,
String^ password
)
new :
serverInstance:string *
userName:string *
password:string -> ServerConnection
public function ServerConnection(
serverInstance : String,
userName : String,
password : String
)
Paramètres
- serverInstance
Type : System. . :: . .String
A String value that specifies the name of the instance of the server with which the connection is established.
- userName
Type : System. . :: . .String
A String value that specifies the logon account used to establish the referenced connection.
- password
Type : System. . :: . .String
A String value that specifies the password used with the logon account.
Exemples
VB
'Declare a ServerConnection object variable to specify SQL authentication, login and password.
Dim conn As New ServerConnection
conn.LoginSecure = False
conn.Login = vlogin
conn.Password = vpassword
'Connect to the local, default instance of SQL Server.
Dim srv As Server
srv = New Server(conn)
'The actual connection is made when a property is retrieved.
Console.WriteLine(srv.Information.Version)
'The connection is automatically disconnected when the Server variable goes out of scope.
PowerShell
$conn = new-object Microsoft.SqlServer.Management.Common.ServerConnection
$conn.LoginSecure = $FALSE
$conn.Login = vlogin
$conn.Password = vpassword
#Connect to the local, default instance of SQL Server
$srv = new-object Microsoft.SqlServer.Management.Smo.Server($conn)
Write-Host $srv.Information.Version
Voir aussi