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Propriété FileGroup

Obtient ou définit le groupe de fichiers dans lequel la table est stockée.

Espace de noms :  Microsoft.SqlServer.Management.Smo
Assembly :  Microsoft.SqlServer.Smo (en Microsoft.SqlServer.Smo.dll)

Syntaxe

'Déclaration
<SfcPropertyAttribute(SfcPropertyFlags.None Or SfcPropertyFlags.ReadOnlyAfterCreation Or SfcPropertyFlags.Standalone)> _
Public Property FileGroup As String
    Get
    Set
'Utilisation
Dim instance As Table
Dim value As String

value = instance.FileGroup

instance.FileGroup = value
[SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.ReadOnlyAfterCreation|SfcPropertyFlags.Standalone)]
public string FileGroup { get; set; }
[SfcPropertyAttribute(SfcPropertyFlags::None|SfcPropertyFlags::ReadOnlyAfterCreation|SfcPropertyFlags::Standalone)]
public:
property String^ FileGroup {
    String^ get ();
    void set (String^ value);
}
[<SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.ReadOnlyAfterCreation|SfcPropertyFlags.Standalone)>]
member FileGroup : string with get, set
function get FileGroup () : String
function set FileGroup (value : String)

Valeur de propriété

Type : System. . :: . .String
Valeur String qui spécifie le groupe de fichiers dans lequel la table est stockée.

Notes

The FileGroup property is set prior to the creation of the table. After the table is created, the property is read-only.

Exemples

The following code example shows how to create a new table and display the time and date that it was created on the console.

C#

Server srv = new Server("(local)");
Database db = srv.Databases["AdventureWorks2008R2"];

Table tb = new Table(db, "Test Table");
Column col1 = new Column(tb, "Name", DataType.NChar(50));
Column col2 = new Column(tb, "ID", DataType.Int);

tb.Columns.Add(col1); 
tb.Columns.Add(col2); 
tb.Create();

Console.WriteLine("The table is part of the " + tb.FileGroup.ToString() + " file group.");

Powershell

$srv = new-Object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("AdventureWorks2008R2")

#Create the Table
$tb = new-object Microsoft.SqlServer.Management.Smo.Table($db, "Test Table")
$col1 = new-object Microsoft.SqlServer.Management.Smo.Column($tb, "Name", [Microsoft.SqlServer.Management.Smo.DataType]::NChar(50))
$col2 = new-object Microsoft.SqlServer.Management.Smo.Column($tb, "ID", [Microsoft.SqlServer.Management.Smo.DataType]::Int)
$tb.Columns.Add($col1)
$tb.Columns.Add($col2)
$tb.Create()

Write-Host "The table is part of the" $tb.FileGroup "file group."