Article
11/18/2011

Tuple<T1, T2, T3, T4, T5, T6>.Item1 Property

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Gets the value of the current Tuple<T1, T2, T3, T4, T5, T6> object's first component.

Namespace: System
Assembly: mscorlib (in mscorlib.dll)

Syntax

'Declaration
Public ReadOnly Property Item1 As T1

public T1 Item1 { get; }

Property Value

Type: T1
The value of the current Tuple<T1, T2, T3, T4, T5, T6> object's first component.

Remarks

You can dynamically determine the type of the Item1 component in one of two ways:

By calling the GetType method on the value that is returned by the Item1 property.
By retrieving the Type object that represents the Tuple<T1, T2, T3, T4, T5, T6> object, and retrieving the first element from the array that is returned by its Type.GetGenericArguments method.

Examples

The following example defines an array of Tuple<T1, T2, T3, T4, T5, T6> objects whose components contain population data for three U.S. cities (New York, Chicago, and Los Angeles) from 1960 through 2000. It then displays a table that lists the data. To display the city name, it retrieves the value of the Item1 property for each Tuple<T1, T2, T3, T4, T5, T6> object.

Module Example
   Public Sub Demo(ByVal outputBlock As System.Windows.Controls.TextBlock)
      ' Create tuples containing population data for New York, Chicago, 
      ' and Los Angeles, 1960-2000.
      Dim cities() = _
           { Tuple.Create("New York", 7781984, 7894862, _ 
                          7071639, 7322564, 8008278), _
             Tuple.Create("Los Angeles", 2479015, 2816061, _ 
                          2966850, 3485398, 3694820), _
             Tuple.Create("Chicago", 3550904, 3366957, _
                          3005072, 2783726, 2896016) }

      ' Display tuple data in table.
      Dim header As String = "Population in"
      outputBlock.Text += String.Format("{0,-12} {1,60}",  _
                        "City", New String("-"c,(60-header.Length)\2) + header + _
                                New String("-"c, (60-header.Length)\2)) + vbCrLf
      outputBlock.Text += String.Format("{0,25}{1,12}{2,12}{3,12}{4,12}",  _
                        "1960", "1970", "1980", "1990", "2000") + vbCrLf                 
      outputBlock.Text &= vbCrLf
      For Each city In cities
         outputBlock.Text += String.Format("{0,-12} {1,12:N0}{2,12:N0}{3,12:N0}{4,12:N0}{5,12:N0}", _
                           city.Item1, city.Item2, city.Item3, city.Item4, _
                           city.Item5, city.Item6) + vbCrLf
      Next
   End Sub
End Module
' The example displays the following output:
'    City          -----------------------Population in-----------------------
'                         1960        1970        1980        1990        2000
'    
'    New York        7,781,984   7,894,862   7,071,639   7,322,564   8,008,278
'    Los Angeles     2,479,015   2,816,061   2,966,850   3,485,398   3,694,820
'    Chicago         3,550,904   3,366,957   3,005,072   2,783,726   2,896,016

using System;
using System.Text.RegularExpressions;

public class Example
{
   public static void Demo(System.Windows.Controls.TextBlock outputBlock)
   {
      // Create tuples containing population data for New York, Chicago, 
      // and Los Angeles, 1960-2000.
      Tuple<string, int, int, int, int, int>[] cities =
           { Tuple.Create("New York", 7781984, 7894862, 7071639, 7322564, 8008278),
             Tuple.Create("Los Angeles", 2479015, 2816061, 2966850, 3485398, 3694820),
             Tuple.Create("Chicago", 3550904, 3366957, 3005072, 2783726, 2896016) };

      // Display tuple data in table.
      string header = "Population in";
      outputBlock.Text += String.Format("{0,-12} {1,60}",
                        "City", new String('-', (60 - header.Length) / 2) + header +
                                new String('-', (60 - header.Length) / 2)) + "\n";
      outputBlock.Text += String.Format("{0,25}{1,12}{2,12}{3,12}{4,12}\n",
                        "1960", "1970", "1980", "1990", "2000") + "\n";

      foreach (var city in cities)
         outputBlock.Text += String.Format("{0,-12} {1,12:N0}{2,12:N0}{3,12:N0}{4,12:N0}{5,12:N0}",
                           city.Item1, city.Item2, city.Item3, city.Item4,
                           city.Item5, city.Item6) + "\n";
   }
}
// The example displays the following output:
//    City          -----------------------Population in-----------------------
//                         1960        1970        1980        1990        2000
//    
//    New York        7,781,984   7,894,862   7,071,639   7,322,564   8,008,278
//    Los Angeles     2,479,015   2,816,061   2,966,850   3,485,398   3,694,820
//    Chicago         3,550,904   3,366,957   3,005,072   2,783,726   2,896,016

Version Information

Silverlight

Supported in: 5, 4

Platforms

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.

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