Table.PositionOf

Syntax

Table.PositionOf(
    table as table,
    row as record,
    optional occurrence as any,
    optional equationCriteria as any
) as any

About

Returns the row position of the first occurrence of the row in the table specified. Returns -1 if no occurrence is found.

• table: The input table.
• row: The row in the table to find the position of.
• occurrence: (Optional) Specifies which occurrences of the row to return.
• equationCriteria: (Optional) Controls the comparison between the table rows.

Example 1

Find the position of the first occurrence of [a = 2, b = 4] in the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}).

Usage

Table.PositionOf(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 1, b = 4],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    [a = 2, b = 4]
)

Output

0

Example 2

Find the position of the second occurrence of [a = 2, b = 4] in the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}).

Usage

Table.PositionOf(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 1, b = 4],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    [a = 2, b = 4],
    1
)

Output

2

Example 3

Find the position of all the occurrences of [a = 2, b = 4] in the table ({[a = 2, b = 4], [a = 6, b = 8], [a = 2, b = 4], [a = 1, b = 4]}).

Usage

Table.PositionOf(
    Table.FromRecords({
        [a = 2, b = 4],
        [a = 1, b = 4],
        [a = 2, b = 4],
        [a = 1, b = 4]
    }),
    [a = 2, b = 4],
    Occurrence.All
)

Output

{0, 2}

Related content

• Occurrence
• Equation criteria