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DbExpressionBuilder.IsOf(DbExpression, TypeUsage) Method

Definition

Creates a new DbIsOfExpression that determines whether the given argument is of the specified type or a subtype.

public:
[System::Runtime::CompilerServices::Extension]
 static System::Data::Common::CommandTrees::DbIsOfExpression ^ IsOf(System::Data::Common::CommandTrees::DbExpression ^ argument, System::Data::Metadata::Edm::TypeUsage ^ type);
public static System.Data.Common.CommandTrees.DbIsOfExpression IsOf (this System.Data.Common.CommandTrees.DbExpression argument, System.Data.Metadata.Edm.TypeUsage type);
static member IsOf : System.Data.Common.CommandTrees.DbExpression * System.Data.Metadata.Edm.TypeUsage -> System.Data.Common.CommandTrees.DbIsOfExpression
<Extension()>
Public Function IsOf (argument As DbExpression, type As TypeUsage) As DbIsOfExpression

Parameters

argument
DbExpression

An expression that specifies the instance.

type
TypeUsage

Type metadata that specifies the type that the instance's result type should be compared to.

Returns

A new DbIsOfExpression with the specified instance and type and DbExpressionKind IsOf.

Exceptions

argument or type is null.

type is not in the same type hierarchy as the result type of argument.

Remarks

DbIsOfExpression requires that argument has a polymorphic result type, and that type is a type from the same type hierarchy as that result type.

Applies to