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XText.NodeType Property

  • Reference

Definition

Namespace:
System.Xml.Linq
Assembly:
System.Xml.XDocument.dll
Assembly:
System.Xml.Linq.dll
Assembly:
netstandard.dll
Source:
XText.cs
Source:
XText.cs
Source:
XText.cs

Gets the node type for this node.

public:
 virtual property System::Xml::XmlNodeType NodeType { System::Xml::XmlNodeType get(); };
public override System.Xml.XmlNodeType NodeType { get; }
member this.NodeType : System.Xml.XmlNodeType
Public Overrides ReadOnly Property NodeType As XmlNodeType

Property Value

XmlNodeType

The node type. For XText objects, this value is Text.

Examples

The following example creates an XML tree that contains a number of types of nodes. It then iterates through the tree, outputting the node type of each node.

Note that Child2 contains an XText node, implicitly converted from the string content.

// Note that XNode uses XmlNodeType, which is in the System.Xml namespace.  
XDocument xmlTree = new XDocument(  
    new XComment("a comment"),  
    new XProcessingInstruction("xml-stylesheet", "type=\"text/xsl\" href=\"hello.xsl\""),  
    new XElement("Root",  
        new XAttribute("Att", "attContent"),  
        new XElement("Child1",  
            new XCData("CDATA content")  
        ),  
        new XElement("Child2", "Text content")  
    )  
);  

foreach (XNode node in xmlTree.DescendantNodes())  
{  
    Console.WriteLine(node.NodeType);  
    if (node.NodeType == XmlNodeType.Element)  
    {  
        foreach (XAttribute att in ((XElement)node).Attributes())  
            Console.WriteLine(att.NodeType);  
    }  
}  

' Note that XNode uses XmlNodeType, which is in the System.Xml namespace.  
Dim xmlTree As XDocument = _  
    <?xml version='1.0'?>  
    <!-- a comment -->  
    <?xml-stylesheet type='text/xsl' href='hello.xsl'?>  
    <Root Att="attContent">  
        <Child1>  
            <![CDATA[CDATA content]]>  
        </Child1>  
        <Child2>Text content</Child2>  
    </Root>  

For Each node As XNode In xmlTree.DescendantNodes  
    Console.WriteLine(node.NodeType.ToString())  
    If node.NodeType = XmlNodeType.Element Then  
        For Each att In DirectCast(node, XElement).Attributes  
            Console.WriteLine(att.NodeType.ToString())  
        Next  
    End If  
Next

This example produces the following output:

Comment  
ProcessingInstruction  
Element  
Attribute  
Element  
CDATA  
Element  
Text

Remarks

Because all classes that derive from XObject contain a NodeType property, you can write code that operates on collections of concrete subclass of XObject. Your code can then test for the node type of each node in the collection.

Applies to

See also