Double.CompareTo(Double) Method
Definition
Important
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Compares two Double
objects numerically.
[Android.Runtime.Register("compareTo", "(Ljava/lang/Double;)I", "")]
public int CompareTo (Java.Lang.Double anotherDouble);
[<Android.Runtime.Register("compareTo", "(Ljava/lang/Double;)I", "")>]
member this.CompareTo : Java.Lang.Double -> int
Parameters
- anotherDouble
- Double
the Double
to be compared.
Returns
the value 0
if anotherDouble
is
numerically equal to this Double
; a value
less than 0
if this Double
is numerically less than anotherDouble
;
and a value greater than 0
if this
Double
is numerically greater than
anotherDouble
.
- Attributes
Exceptions
if object
is null
.
Remarks
Compares two Double
objects numerically.
This method imposes a total order on Double
objects with two differences compared to the incomplete order defined by the Java language numerical comparison operators (<, <=, ==, >=, >
) on double
values.
<ul><li> A NaN is <em>unordered</em> with respect to other values and unequal to itself under the comparison operators. This method chooses to define Double.NaN
to be equal to itself and greater than all other double
values (including Double.POSITIVE_INFINITY
).
<li> Positive zero and negative zero compare equal numerically, but are distinct and distinguishable values. This method chooses to define positive zero (+0.0d
), to be greater than negative zero (-0.0d
). </ul>
This ensures that the natural ordering of Double
objects imposed by this method is consistent with equals; see this discussion for details of floating-point comparison and ordering.
Added in 1.2.
Java documentation for java.lang.Double.compareTo(java.lang.Double)
.
Portions of this page are modifications based on work created and shared by the Android Open Source Project and used according to terms described in the Creative Commons 2.5 Attribution License.