ProcessStartInfo.UseShellExecute Proprietà
Definizione
Importante
Alcune informazioni sono relative alla release non definitiva del prodotto, che potrebbe subire modifiche significative prima della release definitiva. Microsoft non riconosce alcuna garanzia, espressa o implicita, in merito alle informazioni qui fornite.
Ottiene o imposta un valore che indica se usare la shell del sistema operativo per avviare il processo.
public:
property bool UseShellExecute { bool get(); void set(bool value); };
public bool UseShellExecute { get; set; }
member this.UseShellExecute : bool with get, set
Public Property UseShellExecute As Boolean
Valore della proprietà
true
se la shell deve essere utilizzata all'avvio del processo; false
se il processo deve essere creato direttamente dal file eseguibile. Il valore predefinito è true
nelle app .NET Framework e false
nelle app .NET Core.
Eccezioni
Si verifica un tentativo di impostare il valore su true
nelle app UWP (Universal Windows Platform).
Esempio
// Run "cl.exe /cld stdstr.cpp /link /out:sample.exe". UseShellExecute is false because we're specifying
// an executable directly and in this case depending on it being in a PATH folder. By setting
// RedirectStandardOutput to true, the output of cl.exe is directed to the Process.StandardOutput stream
// which is then displayed in this console window directly.
Process^ compiler = gcnew Process;
compiler->StartInfo->FileName = "cl.exe";
compiler->StartInfo->Arguments = "/clr stdstr.cpp /link /out:sample.exe";
compiler->StartInfo->UseShellExecute = false;
compiler->StartInfo->RedirectStandardOutput = true;
compiler->Start();
Console::WriteLine( compiler->StandardOutput->ReadToEnd() );
compiler->WaitForExit();
// Run "csc.exe /r:System.dll /out:sample.exe stdstr.cs". UseShellExecute is false because we're specifying
// an executable directly and in this case depending on it being in a PATH folder. By setting
// RedirectStandardOutput to true, the output of csc.exe is directed to the Process.StandardOutput stream
// which is then displayed in this console window directly.
using (Process compiler = new Process())
{
compiler.StartInfo.FileName = "csc.exe";
compiler.StartInfo.Arguments = "/r:System.dll /out:sample.exe stdstr.cs";
compiler.StartInfo.UseShellExecute = false;
compiler.StartInfo.RedirectStandardOutput = true;
compiler.Start();
Console.WriteLine(compiler.StandardOutput.ReadToEnd());
compiler.WaitForExit();
}
' Run "vbc.exe /reference:Microsoft.VisualBasic.dll /out:sample.exe stdstr.vb". UseShellExecute is False
' because we're specifying an executable directly and in this case depending on it being in a PATH folder.
' By setting RedirectStandardOutput to True, the output of csc.exe is directed to the Process.StandardOutput
' stream which is then displayed in this console window directly.
Using compiler As New Process()
compiler.StartInfo.FileName = "vbc.exe"
compiler.StartInfo.Arguments = "/reference:Microsoft.VisualBasic.dll /out:sample.exe stdstr.vb"
compiler.StartInfo.UseShellExecute = False
compiler.StartInfo.RedirectStandardOutput = True
compiler.Start()
Console.WriteLine(compiler.StandardOutput.ReadToEnd())
compiler.WaitForExit()
End Using
Commenti
Per altre informazioni su questa API, vedere Note sulle API supplementari per ProcessStartInfo.UseShellExecute.