Metodo SqlSpatialServices.Within
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Determina se un valore DbGeometry si trova spazialmente all'interno dell'altro.
Spazio dei nomi: System.Data.Entity.SqlServer
Assembly: EntityFramework.SqlServer (in EntityFramework.SqlServer.dll)
Sintassi
'Dichiarazione
Public Overrides Function Within ( _
geometryValue As DbGeometry, _
otherGeometry As DbGeometry _
) As Boolean
'Utilizzo
Dim instance As SqlSpatialServices
Dim geometryValue As DbGeometry
Dim otherGeometry As DbGeometry
Dim returnValue As Boolean
returnValue = instance.Within(geometryValue, _
otherGeometry)
public override bool Within(
DbGeometry geometryValue,
DbGeometry otherGeometry
)
public:
virtual bool Within(
DbGeometry^ geometryValue,
DbGeometry^ otherGeometry
) override
abstract Within :
geometryValue:DbGeometry *
otherGeometry:DbGeometry -> bool
override Within :
geometryValue:DbGeometry *
otherGeometry:DbGeometry -> bool
public override function Within(
geometryValue : DbGeometry,
otherGeometry : DbGeometry
) : boolean
Parametri
- geometryValue
Tipo: System.Data.Entity.Spatial.DbGeometry
Primo valore geometrico.
- otherGeometry
Tipo: System.Data.Entity.Spatial.DbGeometry
Secondo valore geometrico.
Valore restituito
Tipo: System.Boolean
true se geometryValue si trova all'interno di otherGeometry. In caso contrario, false.