Metodo STWithin

Determines whether the current SqlGeometry is completely within the specified SqlGeometry instance.

Spazio dei nomi  Microsoft.SqlServer.Types
Assembly:  Microsoft.SqlServer.Types (in Microsoft.SqlServer.Types.dll)

Sintassi

'Dichiarazione
<SqlMethodAttribute(IsDeterministic := True, IsPrecise := False)> _
Public Function STWithin ( _
    other As SqlGeometry _
) As SqlBoolean
'Utilizzo
Dim instance As SqlGeometry
Dim other As SqlGeometry
Dim returnValue As SqlBoolean

returnValue = instance.STWithin(other)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public SqlBoolean STWithin(
    SqlGeometry other
)

[SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)]
public:
SqlBoolean STWithin(
    SqlGeometry^ other
)

[<SqlMethodAttribute(IsDeterministic = true, IsPrecise = false)>]
member STWithin : 
        other:SqlGeometry -> SqlBoolean 

public function STWithin(
    other : SqlGeometry
) : SqlBoolean

Parametri

• other
  Tipo: Microsoft.SqlServer.Types. . :: . .SqlGeometry
  The SqlGeometry instance to compare to the current SqlGeometry.

Valore restituito

Tipo: System.Data.SqlTypes. . :: . .SqlBoolean
Returns true if a SqlGeometry instance is completely within another SqlGeometry instance; otherwise, returns false.

Osservazioni

This method always returns null Nothing nullptr unit riferimento Null (Nothing in Visual Basic). if the spatial reference IDs (SRIDs) of the SqlGeometry instances do not match.

Vedere anche

Riferimento

SqlGeometry Classe

Spazio dei nomi Microsoft.SqlServer.Types