Condividi tramite


Metodo CheckIdentityValue

Verifica l'integrità di tutte le colonne di identità nella tabella di riferimento.

Spazio dei nomi  Microsoft.SqlServer.Management.Smo
Assembly:  Microsoft.SqlServer.Smo (in Microsoft.SqlServer.Smo.dll)

Sintassi

'Dichiarazione
Public Function CheckIdentityValue As StringCollection
'Utilizzo
Dim instance As Table
Dim returnValue As StringCollection

returnValue = instance.CheckIdentityValue()
public StringCollection CheckIdentityValue()
public:
StringCollection^ CheckIdentityValue()
member CheckIdentityValue : unit -> StringCollection 
public function CheckIdentityValue() : StringCollection

Valore restituito

Tipo: System.Collections.Specialized. . :: . .StringCollection
Valore dell'oggetto di sistema StringCollection che contiene il valore Identity corrente e il valore della colonna corrente.

Osservazioni

This method is functionally equivalent to the Transact-SQL CHECK IDENT statement. An error will be thrown if this method is called on a table with no Identifier columns.

Esempi

The following code example shows how to check and display the identity value of a table.

C#

Server srv = new Server("(local)");
Database db = srv.Databases["AdventureWorks2008R2"];

Table tb = new Table(db, "Test Table");
Column col1 = new Column(tb, "TableIdentifier", DataType.Int);
col1.Identity = true;
tb.Columns.Add(col1); 

foreach (String s in tb.CheckIdentityValue())
{
   Console.WriteLine(s);
}

Powershell

$srv = new-Object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("AdventureWorks2008R2")

$tb = new-object Microsoft.SqlServer.Management.Smo.Table($db, "Test Table")
$col1 = new-object Microsoft.SqlServer.Management.Smo.Column($tb, "TableIdentifier", [Microsoft.SqlServer.Management.Smo.DataType]::Int)
$col1.Identity = $TRUE
$tb.Columns.Add($col1)

Write-Host $tb.CheckIdentityValue()