Condividi tramite

  • Articolo

Proprietà StartStepID

Gets or sets the ID value of the first job step in the sequence to be executed.

Spazio dei nomi  Microsoft.SqlServer.Management.Smo.Agent
Assembly:  Microsoft.SqlServer.Smo (in Microsoft.SqlServer.Smo.dll)

Sintassi

'Dichiarazione
<SfcPropertyAttribute(SfcPropertyFlags.Standalone)> _
Public Property StartStepID As Integer
    Get
    Set
'Utilizzo
Dim instance As Job
Dim value As Integer

value = instance.StartStepID

instance.StartStepID = value

[SfcPropertyAttribute(SfcPropertyFlags.Standalone)]
public int StartStepID { get; set; }

[SfcPropertyAttribute(SfcPropertyFlags::Standalone)]
public:
property int StartStepID {
    int get ();
    void set (int value);
}

[<SfcPropertyAttribute(SfcPropertyFlags.Standalone)>]
member StartStepID : int with get, set

function get StartStepID () : int
function set StartStepID (value : int)

Valore proprietà

Tipo: System. . :: . .Int32
An Int32 value that specifies the ID value of the first job step in the sequence.

Osservazioni

Microsoft SQL Server Agent job steps are identified by a user-defined, integer value. If no value is specified when you use SQL Server Management Objects (SMO) to create a job, job steps are given an identifier value when the job is added to the Jobs collection of a JobServer object.

By default, the StartStepID value is the value of ID property of the JobStep at the first ordinal position of the JobSteps collection property of the Job object.

Esempi

The following code example creates a job and specifies that the job begins execution on step 4.

C#

Server srv = new Server("(local)");
Job jb = new Job(srv.JobServer, "Test Job");
jb.Create();
jb.StartStepID = 4;

PowerShell

$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$jb = new-object Microsoft.SqlServer.Management.Smo.Agent.Job($srv.JobServer, "Test Job")
$jb.Create()
$jb.StartStepID = 4