Proprietà Database.LogFiles

Articolo
04/26/2013

Gets a collection of LogFile objects. Each LogFile object represents a log file defined on the database.

Spazio dei nomi Microsoft.SqlServer.Management.Smo
Assembly: Microsoft.SqlServer.Smo (in Microsoft.SqlServer.Smo.dll)

Sintassi

'Dichiarazione
<SfcObjectAttribute(SfcContainerRelationship.ChildContainer, SfcContainerCardinality.OneToAny, GetType(LogFile))> _
Public ReadOnly Property LogFiles As LogFileCollection 
    Get
'Utilizzo
Dim instance As Database 
Dim value As LogFileCollection 

value = instance.LogFiles

[SfcObjectAttribute(SfcContainerRelationship.ChildContainer, SfcContainerCardinality.OneToAny, typeof(LogFile))]
public LogFileCollection LogFiles { get; }

[SfcObjectAttribute(SfcContainerRelationship::ChildContainer, SfcContainerCardinality::OneToAny, 
    typeof(LogFile))]
public:
property LogFileCollection^ LogFiles {
    LogFileCollection^ get ();
}

[<SfcObjectAttribute(SfcContainerRelationship.ChildContainer, SfcContainerCardinality.OneToAny, 
    typeof(LogFile))>]
member LogFiles : LogFileCollection

function get LogFiles () : LogFileCollection

Valore proprietà

Tipo: Microsoft.SqlServer.Management.Smo.LogFileCollection
A LogFileCollection object that represents all the log files defined on the database.

Osservazioni

Log files can be referenced by using this collection by specifying the name of the log file. To add a new log file to the collection, call the log file constructor.

Esempi

'Connect to the local, default instance of SQL Server.
Dim srv As Server
srv = New Server

'Reference the AdventureWorks2012 database.
Dim db As Database
db = srv.Databases("AdventureWorks2012")

'Display all the log files in the database.
Dim lf As LogFile
For Each lf In db.LogFiles
   Console.WriteLine(lf.Name)
Next

PowerShell

$srv = new-Object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("AdventureWorks2012")

Foreach ($lf in $db.LogFiles)
{
   Write-Host $lf.Name
}