Condividi tramite

  • Articolo

Enumerable.Min Method (IEnumerable<Decimal>)

Microsoft Silverlight will reach end of support after October 2021. Learn more.

Returns the minimum value in a sequence of Decimal values.

Namespace:  System.Linq
Assembly:  System.Core (in System.Core.dll)

Syntax

'Declaration
<ExtensionAttribute> _
Public Shared Function Min ( _
    source As IEnumerable(Of Decimal) _
) As Decimal

public static decimal Min(
    this IEnumerable<decimal> source
)

Parameters

Return Value

Type: System.Decimal
The minimum value in the sequence.

Usage Note

In Visual Basic and C#, you can call this method as an instance method on any object of type IEnumerable<Decimal>. When you use instance method syntax to call this method, omit the first parameter.

Exceptions

Exception Condition
ArgumentNullException

source is nulla null reference (Nothing in Visual Basic).
InvalidOperationException

source contains no elements.

Remarks

The Min(IEnumerable<Decimal>) method uses the Decimal implementation of IComparable<T> to compare values.

In Visual Basic query expression syntax, an Aggregate Into Min() clause translates to an invocation of Min.

Examples

The following code example demonstrates how to use Min(IEnumerable<Double>) to determine the minimum value in a sequence.

NoteNote:

This code example uses an overload of this overloaded method that is different from the specific overload that this topic describes. To extend the example to this topic, substitute the elements of the source sequence with elements of the appropriate numerical type.

 
      ' Create an array of double values.
      Dim doubles() As Double = {1.5E+104, 9.0E+103, -2.0E+103}

      ' Determine the smallest number in the array.
      Dim min As Double = doubles.Min()

      ' Display the result.
      outputBlock.Text &= "The smallest number is " & min & vbCrLf

      ' This code produces the following output:
      '
      ' The smallest number is -2E+103


      double[] doubles = { 1.5E+104, 9E+103, -2E+103 };

      double min = doubles.Min();

      outputBlock.Text += String.Format("The smallest number is {0}.", min) + "\n";

      /*
       This code produces the following output:

       The smallest number is -2E+103.
      */

Version Information

Silverlight

Supported in: 5, 4, 3

Silverlight for Windows Phone

Supported in: Windows Phone OS 7.1, Windows Phone OS 7.0

XNA Framework

Supported in: Xbox 360, Windows Phone OS 7.0

Platforms

For a list of the operating systems and browsers that are supported by Silverlight, see Supported Operating Systems and Browsers.