次の方法で共有


ContentTypeSchema.ContentTypeName プロパティ

定義

contentTypeName

スキーマ内の次の属性を表します: ma:contentTypeName

[DocumentFormat.OpenXml.SchemaAttr(41, "contentTypeName")]
public DocumentFormat.OpenXml.StringValue ContentTypeName { get; set; }
public DocumentFormat.OpenXml.StringValue ContentTypeName { get; set; }
[DocumentFormat.OpenXml.SchemaAttr(41, "contentTypeName")]
public DocumentFormat.OpenXml.StringValue? ContentTypeName { get; set; }
[DocumentFormat.OpenXml.SchemaAttr("ma:contentTypeName")]
public DocumentFormat.OpenXml.StringValue? ContentTypeName { get; set; }
public DocumentFormat.OpenXml.StringValue? ContentTypeName { get; set; }
member this.ContentTypeName : DocumentFormat.OpenXml.StringValue with get, set
[<DocumentFormat.OpenXml.SchemaAttr(41, "contentTypeName")>]
member this.ContentTypeName : DocumentFormat.OpenXml.StringValue with get, set
[<DocumentFormat.OpenXml.SchemaAttr("ma:contentTypeName")>]
member this.ContentTypeName : DocumentFormat.OpenXml.StringValue with get, set
Public Property ContentTypeName As StringValue

プロパティ値

属性

適用対象