次の方法で共有


Uri.HexEscape(Char) メソッド

定義

指定した文字を等価な 16 進数値に変換します。

public:
 static System::String ^ HexEscape(char character);
public static string HexEscape (char character);
static member HexEscape : char -> string
Public Shared Function HexEscape (character As Char) As String

パラメーター

character
Char

16 進数表現に変換する文字。

戻り値

指定した文字の 16 進数表現。

例外

character が 255 を超えています。

次の例では、文字を等価の 16 進数に変換し、コンソールに書き込みます。

char testChar = 'e';
if ( Uri::IsHexDigit( testChar ) == true )
{
   Console::WriteLine( "'{0}' is the hexadecimal representation of {1}",
      testChar, Uri::FromHex( testChar ) );
}
else
{
   Console::WriteLine( "'{0}' is not a hex character", testChar );
}

String^ returnString = Uri::HexEscape( testChar );
Console::WriteLine( "The hexadecimal value of '{0}' is {1}", testChar, returnString );
char  testChar = 'e';
if (Uri.IsHexDigit(testChar) == true)
    Console.WriteLine("'{0}' is the hexadecimal representation of {1}", testChar, Uri.FromHex(testChar));
else
    Console.WriteLine("'{0}' is not a hexadecimal character", testChar);

string returnString = Uri.HexEscape(testChar);
Console.WriteLine("The hexadecimal value of '{0}' is {1}", testChar, returnString);
let testChar = 'e'
if Uri.IsHexDigit testChar then
    printfn $"'{testChar}' is the hexadecimal representation of {Uri.FromHex testChar}"
else
    printfn $"'{testChar}' is not a hexadecimal character"

let returnString = Uri.HexEscape testChar
printfn $"The hexadecimal value of '{testChar}' is {returnString}"
Dim testChar As Char = "e"c
If Uri.IsHexDigit(testChar) = True Then
    Console.WriteLine("'{0}' is the hexadecimal representation of {1}", testChar, Uri.FromHex(testChar))
Else
    Console.WriteLine("'{0}' is not a hexadecimal character", testChar)
End If 
Dim returnString As String = Uri.HexEscape(testChar)
Console.WriteLine("The hexadecimal value of '{0}' is {1}", testChar, returnString)

適用対象