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Replace Function 

Returns a string in which a specified substring has been replaced with another substring a specified number of times.


Replace(expression, find, replacewith[, start[, count[, compare]]])

Arguments

  • expression
    Required. String expression containing substring to replace.
  • find
    Required. Substring being searched for.
  • replacewith
    Required. Replacement substring.
  • start
    Optional. Position within expression where substring search is to begin. If omitted, 1 is assumed. Must be used in conjunction with count.
  • count
    Optional. Number of substring substitutions to perform. If omitted, the default value is -1, which means make all possible substitutions. Must be used in conjunction with start.
  • compare
    Optional. Numeric value indicating the kind of comparison to use when evaluating substrings. See Settings section for values. If omitted, the default value is 0, which means perform a binary comparison.

Settings

The compare argument can have the following values:

Constant Value Description

vbBinaryCompare

0

Perform a binary comparison.

vbTextCompare

1

Perform a textual comparison.

Return Value

Replace returns the following values:

If Replace returns

expression is zero-length

Zero-length string ("").

expression is Null

An error.

find is zero-length

Copy of expression.

replacewith is zero-length

Copy of expression with all occurrences of find removed.

start > Len(expression)

Zero-length string.

count is 0

Copy of expression.

Remarks

The return value of the Replace function is a string, with substitutions made, that begins at the position specified by start and concludes at the end of the expression string. It is not a copy of the original string from start to finish.

The following example uses the Replace function to return a string:

Dim MyString

' A binary comparison starting at the beginning of the string.

MyString = Replace("XXpXXPXXp", "p", "Y")

' Returns "XXYXXPXXY".



' A textual comparison starting at position 3.

MyString = Replace("XXpXXPXXp", "p", "Y", 3, -1, 1)

' Returns "YXXYXXY".

Requirements

Version 2

See Also

Reference

Filter Function