Grammar.IsStg Property
Definition
Important
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Gets whether a grammar is strongly typed.
protected public:
virtual property bool IsStg { bool get(); };
protected internal virtual bool IsStg { get; }
member this.IsStg : bool
Protected Friend Overridable ReadOnly Property IsStg As Boolean
Property Value
The IsStg
property returns true
if the grammar is strongly-typed; otherwise the property returns false
.
Remarks
A strongly-typed Grammar object (IsStg
equals true
) can return strongly-typed results (objects, rather than raw text) to a client application. For example, a strongly-typed grammar might return DateTime objects rather than raw recognized input.
You can implement strongly-typed grammars by attaching code to the rules of a grammar. As a recognition engine processes any given rule, taking as input the current partial results, the associated code is executed and the textual information becomes rich type objects. This allows a client to more easily make use of enhanced semantic checking, support for multiple cultures, and internal grammar logic.
Instances of strongly-typed Grammar objects are typically obtained from resources in an assembly as a Type of the Common Language Runtime (CLR). The localized types used to support different languages are examples of such Grammar objects.
Notes to Inheritors
Strongly-typed grammars inheriting from Grammar need to override the default behavior of IsStg
, which is to return false
.
Applies to
.NET
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