Point4D.Subtraction(Point4D, Point4D) 연산자
정의
중요
일부 정보는 릴리스되기 전에 상당 부분 수정될 수 있는 시험판 제품과 관련이 있습니다. Microsoft는 여기에 제공된 정보에 대해 어떠한 명시적이거나 묵시적인 보증도 하지 않습니다.
public:
static System::Windows::Media::Media3D::Point4D operator -(System::Windows::Media::Media3D::Point4D point1, System::Windows::Media::Media3D::Point4D point2);
public static System.Windows.Media.Media3D.Point4D operator - (System.Windows.Media.Media3D.Point4D point1, System.Windows.Media.Media3D.Point4D point2);
static member ( - ) : System.Windows.Media.Media3D.Point4D * System.Windows.Media.Media3D.Point4D -> System.Windows.Media.Media3D.Point4D
Public Shared Operator - (point1 As Point4D, point2 As Point4D) As Point4D
매개 변수
반환
point1
과 point2
의 차를 반환합니다.
예제
다음 예제에서는 오버로드된 빼기 연산자를 사용하여 구조체에서 Point4D 구조를 빼는 Point4D 방법을 보여줍니다.
// Subtracts a Point4D from a Point4D using the overloaded - operator.
// Returns a Point4D.
Point4D point1 = new Point4D(10, 5, 1, 4);
Point4D point2 = new Point4D(15, 40, 60, 75);
Point4D pointResult = new Point4D();
pointResult = point1 - point2;
// pointResult is equal to (-5, -35, -59, -71)
// Displaying Results
syntaxString = "pointResult = point1 - point2;";
resultType = "Point4D";
operationString = "Subtracting a Vector3D from a Point4D";
ShowResults(pointResult.ToString(), syntaxString, resultType, operationString);
' Subtracts a Point4D from a Point4D using the overloaded - operator.
' Returns a Point4D.
Dim point1 As New Point4D(10, 5, 1, 4)
Dim point2 As New Point4D(15, 40, 60, 75)
Dim pointResult As New Point4D()
pointResult = point1 - point2
' pointResult is equal to (-5, -35, -59, -71)
' Displaying Results
syntaxString = "pointResult = point1 - point2"
resultType = "Point4D"
operationString = "Subtracting a Vector3D from a Point4D"
ShowResults(pointResult.ToString(), syntaxString, resultType, operationString)