WorksheetFunction.Rank_Eq Method (Excel)
Returns the rank of a number in a list of numbers. The rank of a number is its size relative to other values in a list. (If you were to sort the list, the rank of the number would be its position.)
Version Information
추가된 버전: Excel 2010
Syntax
식 .Rank_Eq(Arg1, Arg2, Arg3)
식 A variable that represents a WorksheetFunction object.
Parameters
Name |
Required/Optional |
Data Type |
Description |
|---|---|---|---|
Arg1 |
필수 |
Double |
Number - The number whose rank you want to find. |
Arg2 |
필수 |
Range |
Ref - An array of, or a reference to, a list of numbers. Non-numeric values in reference are ignored. |
Arg3 |
선택 |
Variant |
Order - A number that specifies how to rank the number. |
Return Value
Double
Remarks
If the order is 0 (zero) or omitted, Microsoft Excel ranks the number as if the reference was a list sorted in descending order.
If the order is any non-zero value, Microsoft Excel ranks the number as if the reference was a list sorted in ascending order.
RANK_EQ gives duplicate numbers the same rank. However, the presence of duplicate numbers affects the ranks of subsequent numbers. For example, in a list of integers sorted in ascending order, if the number 10 appears twice and has a rank of 5, then 11 would have a rank of 7 (no number would have a rank of 6).
For some purposes you might want to use a definition of rank that takes ties into account. In the previous example, you would want a revised rank of 5.5 for the number 10. To do this, add the following correction factor to the value returned by RANK_EQ. This correction factor is appropriate both for the case where rank is computed in descending order (order = 0 or omitted) or ascending order (order = nonzero value). Correction factor for tied ranks=[COUNT(ref) + 1 – RANK_EQ(number, ref, 0) – RANK_EQ(number, ref, 1)]/2. In the following example, RANK_EQ(A2,A1:A5,1) equals 3. The correction factor is (5 + 1 – 2 – 3)/2 = 0.5 and the revised rank that takes ties into account is 3 + 0.5 = 3.5. If number occurs only once in ref, the correction factor will be 0, since RANK_EQ would not have to be adjusted for a tie.