is_compound Class

Tests if the specified type is not fundamental.

Syntax

template <class Ty>
struct is_compound;

Parameters

Ty
The type to query.

Remarks

An instance of the type predicate holds false if the type of Ty is a fundamental type (that is, if is_fundamental<Ty> holds true); otherwise, it holds true. Thus, the predicate holds true if Ty is an array type, a function type, a pointer to void or an object or a function, a reference, a class, a union, an enumeration, or a pointer to non-static class member, or a cv-qualified form of one of them.

Example

// std__type_traits__is_compound.cpp
// compile with: /EHsc
#include <type_traits>
#include <iostream>

struct trivial
    {
    int val;
    };

int main()
    {
    std::cout << "is_compound<trivial> == " << std::boolalpha
        << std::is_compound<trivial>::value << std::endl;
    std::cout << "is_compound<int[]> == " << std::boolalpha
        << std::is_compound<int[]>::value << std::endl;
    std::cout << "is_compound<int()> == " << std::boolalpha
        << std::is_compound<int()>::value << std::endl;
    std::cout << "is_compound<int&> == " << std::boolalpha
        << std::is_compound<int&>::value << std::endl;
    std::cout << "is_compound<void *> == " << std::boolalpha
        << std::is_compound<void *>::value << std::endl;
    std::cout << "is_compound<int> == " << std::boolalpha
        << std::is_compound<int>::value << std::endl;

    return (0);
    }

is_compound<trivial> == true
is_compound<int[]> == true
is_compound<int()> == true
is_compound<int&> == true
is_compound<void *> == true
is_compound<int> == false

Requirements

Header: <type_traits>

Namespace: std

See also

<type_traits>
is_class Class