DbExpressionBuilder.IsOf(DbExpression, TypeUsage) Method
Definition
Important
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Creates a new DbIsOfExpression that determines whether the given argument is of the specified type or a subtype.
public:
[System::Runtime::CompilerServices::Extension]
static System::Data::Common::CommandTrees::DbIsOfExpression ^ IsOf(System::Data::Common::CommandTrees::DbExpression ^ argument, System::Data::Metadata::Edm::TypeUsage ^ type);
public static System.Data.Common.CommandTrees.DbIsOfExpression IsOf (this System.Data.Common.CommandTrees.DbExpression argument, System.Data.Metadata.Edm.TypeUsage type);
static member IsOf : System.Data.Common.CommandTrees.DbExpression * System.Data.Metadata.Edm.TypeUsage -> System.Data.Common.CommandTrees.DbIsOfExpression
<Extension()>
Public Function IsOf (argument As DbExpression, type As TypeUsage) As DbIsOfExpression
Parameters
- argument
- DbExpression
An expression that specifies the instance.
- type
- TypeUsage
Type metadata that specifies the type that the instance's result type should be compared to.
Returns
A new DbIsOfExpression with the specified instance and type and DbExpressionKind IsOf.
Exceptions
argument
or type
is null.
type
is not in the same type hierarchy as the result type of argument
.
Remarks
DbIsOfExpression requires that argument
has a polymorphic result type, and that type
is a type from the same type hierarchy as that result type.
Applies to
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