CTypeExpressionSyntax.WithType(TypeSyntax) Method

Definition

Returns a copy of this with the Type property changed to the specified value. Returns this instance if the specified value is the same as the current value.

public:
 Microsoft::CodeAnalysis::VisualBasic::Syntax::CTypeExpressionSyntax ^ WithType(Microsoft::CodeAnalysis::VisualBasic::Syntax::TypeSyntax ^ type);
public Microsoft.CodeAnalysis.VisualBasic.Syntax.CTypeExpressionSyntax WithType (Microsoft.CodeAnalysis.VisualBasic.Syntax.TypeSyntax type);
override this.WithType : Microsoft.CodeAnalysis.VisualBasic.Syntax.TypeSyntax -> Microsoft.CodeAnalysis.VisualBasic.Syntax.CTypeExpressionSyntax
Public Function WithType (type As TypeSyntax) As CTypeExpressionSyntax

Parameters

type
TypeSyntax

Returns

Applies to