Type.IsPointer Свойство
Определение
Важно!
Некоторые сведения относятся к предварительной версии продукта, в которую до выпуска могут быть внесены существенные изменения. Майкрософт не предоставляет никаких гарантий, явных или подразумеваемых, относительно приведенных здесь сведений.
Возвращает значение, указывающее, является ли объект Type указателем.
public:
virtual property bool IsPointer { bool get(); };
public:
property bool IsPointer { bool get(); };
public virtual bool IsPointer { get; }
public bool IsPointer { get; }
member this.IsPointer : bool
Public Overridable ReadOnly Property IsPointer As Boolean
Public ReadOnly Property IsPointer As Boolean
Значение свойства
Значение true
, если Type является указателем; в противном случае — значение false
.
Реализации
Примеры
В следующем примере показано использование IsPointer
Свойства.
using namespace System;
using namespace System::Reflection;
public ref class MyTypeDelegator: public TypeDelegator
{
public:
String^ myElementType;
private:
Type^ myType;
public:
MyTypeDelegator( Type^ myType )
: TypeDelegator( myType )
{
this->myType = myType;
}
protected:
// Override Type::HasElementTypeImpl().
virtual bool HasElementTypeImpl() override
{
// Determine whether the type is an array.
if ( myType->IsArray )
{
myElementType = "array";
return true;
}
// Determine whether the type is a reference.
if ( myType->IsByRef )
{
myElementType = "reference";
return true;
}
// Determine whether the type is a pointer.
if ( myType->IsPointer )
{
myElementType = "pointer";
return true;
}
// Return false if the type is not a reference, array, or pointer type.
return false;
}
};
int main()
{
try
{
int myInt = 0;
array<Int32>^myArray = gcnew array<Int32>(5);
MyTypeDelegator^ myType = gcnew MyTypeDelegator( myArray->GetType() );
// Determine whether myType is an array, pointer, reference type.
Console::WriteLine( "\nDetermine whether a variable is an array, pointer, or reference type.\n" );
if ( myType->HasElementType )
Console::WriteLine( "The type of myArray is {0}.", myType->myElementType );
else
Console::WriteLine( "myArray is not an array, pointer, or reference type." );
myType = gcnew MyTypeDelegator( myInt.GetType() );
// Determine whether myType is an array, pointer, reference type.
if ( myType->HasElementType )
Console::WriteLine( "The type of myInt is {0}.", myType->myElementType );
else
Console::WriteLine( "myInt is not an array, pointer, or reference type." );
}
catch ( Exception^ e )
{
Console::WriteLine( "Exception: {0}", e->Message );
}
}
using System;
using System.Reflection;
public class MyTypeDelegator : TypeDelegator
{
public string myElementType = null;
private Type myType = null ;
public MyTypeDelegator(Type myType) : base(myType)
{
this.myType = myType;
}
// Override Type.HasElementTypeImpl().
protected override bool HasElementTypeImpl()
{
// Determine whether the type is an array.
if(myType.IsArray)
{
myElementType = "array";
return true;
}
// Determine whether the type is a reference.
if(myType.IsByRef)
{
myElementType = "reference";
return true;
}
// Determine whether the type is a pointer.
if(myType.IsPointer)
{
myElementType = "pointer";
return true;
}
// Return false if the type is not a reference, array, or pointer type.
return false;
}
}
public class Type_HasElementTypeImpl
{
public static void Main()
{
try
{
int myInt = 0 ;
int[] myArray = new int[5];
MyTypeDelegator myType = new MyTypeDelegator(myArray.GetType());
// Determine whether myType is an array, pointer, reference type.
Console.WriteLine("\nDetermine whether a variable is an array, pointer, or reference type.\n");
if( myType.HasElementType)
Console.WriteLine("The type of myArray is {0}.", myType.myElementType);
else
Console.WriteLine("myArray is not an array, pointer, or reference type.");
myType = new MyTypeDelegator(myInt.GetType());
// Determine whether myType is an array, pointer, reference type.
if( myType.HasElementType)
Console.WriteLine("The type of myInt is {0}.", myType.myElementType);
else
Console.WriteLine("myInt is not an array, pointer, or reference type.");
}
catch( Exception e )
{
Console.WriteLine("Exception: {0}", e.Message);
}
}
}
Imports System.Reflection
Public Class MyTypeDelegator
Inherits TypeDelegator
Public myElementType As String = Nothing
Private myType As Type = Nothing
Public Sub New(ByVal myType As Type)
MyBase.New(myType)
Me.myType = myType
End Sub
' Override Type.HasElementTypeImpl().
Protected Overrides Function HasElementTypeImpl() As Boolean
' Determine whether the type is an array.
If myType.IsArray Then
myElementType = "array"
Return True
End If
' Determine whether the type is a reference.
If myType.IsByRef Then
myElementType = "reference"
Return True
End If
' Determine whether the type is a pointer.
If myType.IsPointer Then
myElementType = "pointer"
Return True
End If
' The type is not a reference, array, or pointer type.
Return False
End Function 'HasElementTypeImpl
End Class
Public Class Type_HasElementTypeImpl
Public Shared Sub Main()
Try
Dim myInt As Integer = 0
Dim myArray(4) As Integer
Dim myType As New MyTypeDelegator(myArray.GetType())
Console.WriteLine(ControlChars.NewLine + "Determine whether a variable refers to an array or pointer or reference type." + ControlChars.NewLine)
' Determine whether myType is an array, pointer, reference type.
If myType.HasElementType Then
Console.WriteLine("The type of myArray is {0}.", myType.myElementType.ToString())
Else
Console.WriteLine("myArray is not an array, pointer, or reference type.")
End If
myType = New MyTypeDelegator(myInt.GetType())
' Determine whether myType is an array, pointer, reference type.
If myType.HasElementType Then
Console.WriteLine("The type of myInt is {0}.", myType.myElementType.ToString())
Else
Console.WriteLine("myInt is not an array, pointer, or reference type.")
End If
Catch e As Exception
Console.WriteLine("Exception: {0}", e.Message.ToString())
End Try
End Sub
End Class
Комментарии
Если текущий объект Type представляет универсальный тип или параметр типа в определении универсального типа или универсального метода, это свойство всегда возвращает значение false
.
Это свойство доступно только для чтения.