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PenInputPanelChangedEventHandler - делегат

  • Статья

Обновлен: Ноябрь 2007

Represents the method that handles the PanelChanged event of a PenInputPanel object.

Пространство имен:  Microsoft.Ink
Сборка:  Microsoft.Ink (в Microsoft.Ink.dll)

Синтаксис

'Декларация
Public Delegate Sub PenInputPanelChangedEventHandler ( _
    sender As Object, _
    e As PenInputPanelChangedEventArgs _
)
'Применение
Dim instance As New PenInputPanelChangedEventHandler(AddressOf HandlerMethod)

public delegate void PenInputPanelChangedEventHandler(
    Object sender,
    PenInputPanelChangedEventArgs e
)

public delegate void PenInputPanelChangedEventHandler(
    Object^ sender, 
    PenInputPanelChangedEventArgs^ e
)

/** @delegate */
public delegate void PenInputPanelChangedEventHandler(
    Object sender,
    PenInputPanelChangedEventArgs e
)

JScript не поддерживает делегаты.

Параметры

Заметки

When creating a PenInputPanel object, the PanelType panel is the default panel. If the panel is changed by setting the CurrentPanel property before the pen input panel becomes active for the first time, a PanelChanged event occurs.

Примеры

This C# example creates a PenInputPanel object, thePenInputPanel, and attaches it to an InkEdit control, theInkEdit. The example then adds a PanelChanged event handler to thePenInputPanel. The PanelChanged handler sets the text of the attached InkEdit control to a sentence containing the new panel type.

[C#]

//...

// Delcare the PenInputPanel object
PenInputPanel thePenInputPanel;

public Form1()
{
    // Required for Windows Form Designer support
    InitializeComponent();

    // Create and attach the new PenInputPanel to an InkEdit control.
    thePenInputPanel = new PenInputPanel(theInkEdit);

    // Add a PanelChanged event handler
    thePenInputPanel.PanelChanged +=
        new PenInputPanelChangedEventHandler(PanelChanged_Event);
}

//...

public void PanelChanged_Event(object sender,
 PenInputPanelChangedEventArgs e)
{
    // Make sure the object that generated
    // the event is a PenInputPanel object
    if (sender is PenInputPanel)
    {
        PenInputPanel theSenderPanel = (PenInputPanel)sender;

        theSenderPanel.AttachedEditControl.Text = "The panel has changed to ";
        theSenderPanel.AttachedEditControl.Text += e.NewPanelType.ToString();
    }
}

This Microsoft® Visual Basic® .NET example creates a PenInputPanel object, thePenInputPanel, and attaches it to an InkEdit control, theInkEdit. The example then adds a PanelChanged event handler to thePenInputPanel. The PanelChanged handler sets the text of the attached InkEdit control to a sentence containing the new panel type.

[Visual Basic]

'...

' Declare the PenInputPanel object
Dim thePenInputPanel As PenInputPanel

Public Sub New()
    MyBase.New()

    'This call is required by the Windows Form Designer.
    InitializeComponent()

    ' Create and attach the new PenInputPanel to an InkEdit control.
    thePenInputPanel = New PenInputPanel(theInkEdit)

   ' Add a PanelChanged event handler
   AddHandler thePenInputPanel.PanelChanged, AddressOf PanelChanged_Event
End Sub 'New

'...

Public Sub PanelChanged_Event(ByVal sender As Object, ByVal e As _
                              PenInputPanelChangedEventArgs)
    ' Make sure the object that generated
    ' the event is a PenInputPanel object
    If TypeOf sender Is PenInputPanel Then
        Dim theSenderPanel As PenInputPanel = CType(sender, PenInputPanel)

        theSenderPanel.AttachedEditControl.Text = "The panel has changed to "
        theSenderPanel.AttachedEditControl.Text += e.NewPanelType.ToString
    End If
End Sub 'PanelChanged_Event

Платформы

Windows Vista

Среды .NET Framework и .NET Compact Framework поддерживают не все версии каждой платформы. Поддерживаемые версии перечислены в разделе Требования к системе для .NET Framework.

Сведения о версии

.NET Framework

Поддерживается в версии: 3.0

См. также

Ссылки

Microsoft.Ink - пространство имен

PenInputPanel.OnPanelChanged