Свойство PartitionSchemes
Represents a collection of PartitionScheme objects. Each PartitionScheme object represents a partition scheme defined on the database.
Пространство имен: Microsoft.SqlServer.Management.Smo
Сборка: Microsoft.SqlServer.Smo (в Microsoft.SqlServer.Smo.dll)
Синтаксис
'Декларация
<SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny, _
GetType(PartitionScheme))> _
Public ReadOnly Property PartitionSchemes As PartitionSchemeCollection
Get
'Применение
Dim instance As Database
Dim value As PartitionSchemeCollection
value = instance.PartitionSchemes
[SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny,
typeof(PartitionScheme))]
public PartitionSchemeCollection PartitionSchemes { get; }
[SfcObjectAttribute(SfcContainerRelationship::ObjectContainer, SfcContainerCardinality::ZeroToAny,
typeof(PartitionScheme))]
public:
property PartitionSchemeCollection^ PartitionSchemes {
PartitionSchemeCollection^ get ();
}
[<SfcObjectAttribute(SfcContainerRelationship.ObjectContainer, SfcContainerCardinality.ZeroToAny,
typeof(PartitionScheme))>]
member PartitionSchemes : PartitionSchemeCollection
function get PartitionSchemes () : PartitionSchemeCollection
Значение свойства
Тип Microsoft.SqlServer.Management.Smo. . :: . .PartitionSchemeCollection
A PartitionSchemeCollection object that represents all the partition schemes defined on the database.
Замечания
Specific partition schemes can be referenced by using this collection by specifying the name of the partition scheme. To add a new partition scheme to the collection, call the partition scheme constructor.
Примеры
Dim srv As Server
srv = New Server
'Reference the AdventureWorks database.
Dim db As Database
db = srv.Databases("AdventureWorks")
'Display all the partition functions and schemes on the database.
Dim pf As PartitionFunction
For Each pf In db.PartitionFunctions
Console.WriteLine(pf.Name)
Next
Dim ps As PartitionScheme
For Each ps In db.PartitionSchemes
Console.WriteLine(ps.Name)
Next