Свойство Job.JobType

Статья
04/26/2013

Gets the job type, which specifies whether the job is local or multiserver.

Пространство имен: Microsoft.SqlServer.Management.Smo.Agent
Сборка: Microsoft.SqlServer.Smo (в Microsoft.SqlServer.Smo.dll)

Синтаксис

'Декларация
<SfcPropertyAttribute(SfcPropertyFlags.None Or SfcPropertyFlags.Expensive Or SfcPropertyFlags.Standalone)> _
Public ReadOnly Property JobType As JobType 
    Get
'Применение
Dim instance As Job 
Dim value As JobType 

value = instance.JobType

[SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.Expensive|SfcPropertyFlags.Standalone)]
public JobType JobType { get; }

[SfcPropertyAttribute(SfcPropertyFlags::None|SfcPropertyFlags::Expensive|SfcPropertyFlags::Standalone)]
public:
property JobType JobType {
    JobType get ();
}

[<SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.Expensive|SfcPropertyFlags.Standalone)>]
member JobType : JobType

function get JobType () : JobType

Значение свойства

Тип: Microsoft.SqlServer.Management.Smo.Agent.JobType
A JobType object value that specifies the job type, which is either local or multiserver.

Примеры

The following code example creates a job and displays its type.

Server srv = new Server("(local)");
Job jb = new Job(srv.JobServer, "Test Job");
jb.Create();
Console.WriteLine(jb.JobType.ToString());

PowerShell

$srv = new-object Microsoft.SqlServer.Management.Smo.Server("(local)")
$jb = new-object Microsoft.SqlServer.Management.Smo.Agent.Job($srv.JobServer, "Test Job")
$jb.Create()
Write-Host $jb.JobType