Свойство Database.DefaultFileGroup

Статья
04/26/2013

Gets the default file group used by the database.

Пространство имен: Microsoft.SqlServer.Management.Smo
Сборка: Microsoft.SqlServer.Smo (в Microsoft.SqlServer.Smo.dll)

Синтаксис

'Декларация
<SfcPropertyAttribute(SfcPropertyFlags.None Or SfcPropertyFlags.Expensive Or SfcPropertyFlags.Standalone)> _
Public ReadOnly Property DefaultFileGroup As String 
    Get
'Применение
Dim instance As Database 
Dim value As String 

value = instance.DefaultFileGroup

[SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.Expensive|SfcPropertyFlags.Standalone)]
public string DefaultFileGroup { get; }

[SfcPropertyAttribute(SfcPropertyFlags::None|SfcPropertyFlags::Expensive|SfcPropertyFlags::Standalone)]
public:
virtual property String^ DefaultFileGroup {
    String^ get () sealed;
}

[<SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.Expensive|SfcPropertyFlags.Standalone)>]
abstract DefaultFileGroup : string
[<SfcPropertyAttribute(SfcPropertyFlags.None|SfcPropertyFlags.Expensive|SfcPropertyFlags.Standalone)>]
override DefaultFileGroup : string

final function get DefaultFileGroup () : String

Значение свойства

Тип: System.String
A String value that specifies the default file group for the database.

Реализует

IDatabaseOptions.DefaultFileGroup

Замечания

The default file group is the file group that is used when a database is created and the file group is not specified.

Примеры

'Connect to the local, default instance of SQL Server.
Dim srv As Server
srv = New Server

'Reference the AdventureWorks2012 database.
Dim db As Database
db = srv.Databases("AdventureWorks2012")

'Display information about the database.
Console.WriteLine("Name = " + db.Name.ToString)
Console.WriteLine("ID = " + db.ID.ToString)
Console.WriteLine("Owner = " + db.Owner.ToString)
Console.WriteLine("Parent = " + db.Parent.ToString)
Console.WriteLine("State = " + db.State.ToString)
Console.WriteLine("Status = " + db.Status.ToString)
Console.WriteLine("User Name = " + db.UserName.ToString)
Console.WriteLine("DBO Login = " + db.DboLogin.ToString)
Console.WriteLine("Version = " + db.Version.ToString)
Console.WriteLine("Service Broker = " + _
db.ServiceBroker.ToString)
Console.WriteLine("Replication Options = " + _
db.ReplicationOptions.ToString)
Console.WriteLine("Default File Group = " + _
db.DefaultFileGroup.ToString)
Console.WriteLine("Default FTS catalog = " + _
db.DefaultFullTextCatalog.ToString)
Console.WriteLine("Default Schema = " + _
db.DefaultSchema.ToString)

PowerShell

$srv = new-Object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("AdventureWorks2012")

Write-Host "Name =" $db.Name
Write-Host "ID =" $db.ID
Write-Host "Owner =" $db.Ownder
Write-Host "Parent =" $db.Parent
Write-Host "State =" $db.State
Write-Host "Status =" $db.Status
Write-Host "User Name =" $db.UserName
Write-Host "DBO Login =" $db.DboLogin
Write-Host "Version =" $db.Version
Write-Host "Service Broker =" $db.ServiceBroker
Write-Host "Replication Options =" $db.ReplicationOptions
Write-Host "Default File Group =" $db.DefaultFileGroup
Write-Host "Default FTS catalog =" $db.DefaultFullTextCatalog
Write-Host "Default Schema =" $db.DefaultSchema