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FileSystem.LineInput(Int32) Method

Definition

Reads a single line from an open sequential file and assigns it to a String variable.

public:
 static System::String ^ LineInput(int FileNumber);
public static string LineInput (int FileNumber);
static member LineInput : int -> string
Public Function LineInput (FileNumber As Integer) As String

Parameters

FileNumber
Int32

Required. Any valid file number.

Returns

Reads a single line from an open sequential file and assigns it to a String variable.

Exceptions

End of file reached.

FileNumber does not exist.

Examples

This example uses the LineInput function to read a line from a sequential file and assign it to a variable. This example assumes that TestFile is a text file that has several lines of sample data.

Dim TextLine As String
' Open file.
FileOpen(1, "TESTFILE", OpenMode.Input)
' Loop until end of file.
While Not EOF(1)
    ' Read line into variable.
    TextLine = LineInput(1)
    ' Print to the console.
    Console.WriteLine("1", TextLine)
End While
FileClose(1)

Remarks

The LineInput function is provided for backward compatibility and may affect performance. For non-legacy applications, the My.Computer.FileSystem object provides better performance. For more information, see File Access with Visual Basic.

Data read with LineInput is usually written to a file by using Print.

Important

When reading from files, do not make decisions about the contents of a file based on the file name extension. For example, a file that is named Form1.vb may not be a Visual Basic source file.

The LineInput function reads from a file one character at a time until it encounters a carriage return (Chr(13)) or carriage return/line feed (Chr(13) + Chr(10)) sequence. Carriage return/line feed sequences are skipped instead of appended to the character string.

Important

Reading from a file by using the LineInput function requires Read access from the FileIOPermissionAccess enumeration.

Applies to

See also