ProcessStartInfo.UseShellExecute Property

Reference

Definition

Namespace:: System.Diagnostics

Assembly:: System.Diagnostics.Process.dll

Assembly:: System.dll

Assembly:: netstandard.dll

Source:: ProcessStartInfo.Unix.cs

Source:: ProcessStartInfo.Unix.cs

Source:: ProcessStartInfo.Unix.cs

Important

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Gets or sets a value indicating whether to use the operating system shell to start the process.

public:
 property bool UseShellExecute { bool get(); void set(bool value); };

public bool UseShellExecute { get; set; }

member this.UseShellExecute : bool with get, set

Public Property UseShellExecute As Boolean

Property Value

Boolean

true if the shell should be used when starting the process; false if the process should be created directly from the executable file. The default is true on .NET Framework apps and false on .NET Core apps.

Exceptions

PlatformNotSupportedException

An attempt to set the value to true on Universal Windows Platform (UWP) apps occurs.

Examples

// Run "cl.exe /cld stdstr.cpp /link /out:sample.exe". UseShellExecute is false because we're specifying
// an executable directly and in this case depending on it being in a PATH folder. By setting
// RedirectStandardOutput to true, the output of cl.exe is directed to the Process.StandardOutput stream
// which is then displayed in this console window directly.    
Process^ compiler = gcnew Process;
compiler->StartInfo->FileName = "cl.exe";
compiler->StartInfo->Arguments = "/clr stdstr.cpp /link /out:sample.exe";
compiler->StartInfo->UseShellExecute = false;
compiler->StartInfo->RedirectStandardOutput = true;
compiler->Start();

Console::WriteLine( compiler->StandardOutput->ReadToEnd() );

compiler->WaitForExit();

// Run "csc.exe /r:System.dll /out:sample.exe stdstr.cs". UseShellExecute is false because we're specifying
// an executable directly and in this case depending on it being in a PATH folder. By setting
// RedirectStandardOutput to true, the output of csc.exe is directed to the Process.StandardOutput stream
// which is then displayed in this console window directly.
using (Process compiler = new Process())
{
    compiler.StartInfo.FileName = "csc.exe";
    compiler.StartInfo.Arguments = "/r:System.dll /out:sample.exe stdstr.cs";
    compiler.StartInfo.UseShellExecute = false;
    compiler.StartInfo.RedirectStandardOutput = true;
    compiler.Start();

    Console.WriteLine(compiler.StandardOutput.ReadToEnd());

    compiler.WaitForExit();
}

' Run "vbc.exe /reference:Microsoft.VisualBasic.dll /out:sample.exe stdstr.vb". UseShellExecute is False 
' because we're specifying an executable directly and in this case depending on it being in a PATH folder. 
' By setting RedirectStandardOutput to True, the output of csc.exe is directed to the Process.StandardOutput 
' stream which is then displayed in this console window directly.    
Using compiler As New Process()
    compiler.StartInfo.FileName = "vbc.exe"
    compiler.StartInfo.Arguments = "/reference:Microsoft.VisualBasic.dll /out:sample.exe stdstr.vb"
    compiler.StartInfo.UseShellExecute = False
    compiler.StartInfo.RedirectStandardOutput = True
    compiler.Start()

    Console.WriteLine(compiler.StandardOutput.ReadToEnd())

    compiler.WaitForExit()
End Using

Remarks

For more information about this API, see Supplemental API remarks for ProcessStartInfo.UseShellExecute.

Applies to

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