Double.Exp2M1(Double) 方法

定义

2计算升至给定幂并减去一个。

public:
 static double Exp2M1(double x) = System::Numerics::IExponentialFunctions<double>::Exp2M1;
public static double Exp2M1 (double x);
static member Exp2M1 : double -> double
Public Shared Function Exp2M1 (x As Double) As Double

参数

x
Double

所引发的 2 幂。

返回

2x - 1

实现

适用于