通过

_rotr8、_rotr16

  • 项目

Microsoft 专用

通过指定的位位置数将输入值向右旋转到最高有效位 (MSB)。

语法

unsigned char _rotr8(
   unsigned char value,
   unsigned char shift
);
unsigned short _rotr16(
   unsigned short value,
   unsigned char shift
);

参数

value
[in] 要旋转的值。

shift
[in] 要旋转的位数。

返回值

旋转的值。

要求

Intrinsic 体系结构
_rotr8 x86、ARM、x64、ARM64
_rotr16 x86、ARM、x64、ARM64

头文件<intrin.h>

备注

不像右位移操作，当执行向右旋转时，离开低端的低顺序位将移动到高顺序位位置。

示例

// rotr.cpp
#include <stdio.h>
#include <intrin.h>

#pragma intrinsic(_rotr8, _rotr16)

int main()
{
    unsigned char c = 'A', c1, c2;

    for (int i = 0; i < 8; i++)
    {
       printf_s("Rotating 0x%x right by %d bits gives 0x%x\n", c,
                i, _rotr8(c, i));
    }

    unsigned short s = 0x12;
    int nBit = 10;

    printf_s("Rotating unsigned short 0x%x right by %d bits "
             "gives 0x%x\n",
            s, nBit, _rotr16(s, nBit));
}

Rotating 0x41 right by 0 bits gives 0x41
Rotating 0x41 right by 1 bits gives 0xa0
Rotating 0x41 right by 2 bits gives 0x50
Rotating 0x41 right by 3 bits gives 0x28
Rotating 0x41 right by 4 bits gives 0x14
Rotating 0x41 right by 5 bits gives 0xa
Rotating 0x41 right by 6 bits gives 0x5
Rotating 0x41 right by 7 bits gives 0x82
Rotating unsigned short 0x12 right by 10 bits gives 0x480

结束 Microsoft 专用

另请参阅

_rotl8, _rotl16
编译器内部函数