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<complex> 运算符

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operator!=

测试两个复数是否不相等，这两个复数或其中一个可能属于其类型与实部和虚部的类型相同的子集。

template <class Type>
bool operator!=(
    const complex<Type>& left,
    const complex<Type>& right);

template <class Type>
bool operator!=(
    const complex<Type>& left,
    const Type& right);

template <class Type>
bool operator!=(
    const Type& left,
    const complex<Type>& right);

参数

left
将测试其不等性的复数或与复数的参数类型相同的对象。

right
将测试其不等性的复数或与复数的参数类型相同的对象。

返回值

如果数字不相等，则为 true；如果数字相等，则为 false。

注解

当且仅当实部和虚部都相等时，两个复数才相等。 否则，它们不相等。

重载该操作，以便可以执行比较测试，而无需将数据转换为特定格式。

示例

// complex_op_NE.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Example of the first member function
   // type complex<double> compared with type complex<double>
   complex <double> cl1 ( polar (3.0, pi / 6 ) );
   complex <double> cr1a ( polar (3.0, pi /6 ) );
   complex <double> cr1b ( polar (2.0, pi / 3 ) );

   cout << "The left-side complex number is cl1 = " << cl1 << endl;
   cout << "The 1st right-side complex number is cr1a = " << cr1a << endl;
   cout << "The 2nd right-side complex number is cr1b = " << cr1b << endl;
   if ( cl1 != cr1a )
      cout << "The complex numbers cl1 & cr1a are not equal." << endl;
   else
      cout << "The complex numbers cl1 & cr1a are equal." << endl;
   if ( cl1 != cr1b )
      cout << "The complex numbers cl1 & cr1b are not equal." << endl;
   else
      cout << "The complex numbers cl1 & cr1b are equal." << endl;
   cout << endl;

   // Example of the second member function
   // type complex<int> compared with type int
   complex <int> cl2a ( 3, 4 );
   complex <int> cl2b ( 5,0 );
   int cr2a =3;
   int cr2b =5;

   cout << "The 1st left-side complex number is cl2a = " << cl2a << endl;
   cout << "The 1st right-side complex number is cr2a = " << cr2a << endl;
   if ( cl2a != cr2a )
      cout << "The complex numbers cl2a & cr2a are not equal." << endl;
   else
      cout << "The complex numbers cl2a & cr2a are equal." << endl;

   cout << "The 2nd left-side complex number is cl2b = " << cl2b << endl;
   cout << "The 2nd right-side complex number is cr2b = " << cr2b << endl;
   if ( cl2b != cr2b )
      cout << "The complex numbers cl2b & cr2b are not equal." << endl;
   else
      cout << "The complex numbers cl2b & cr2b are equal." << endl;
   cout << endl;

   // Example of the third member function
   // type double compared with type complex<double>
   double cl3a =3;
   double cl3b =5;
   complex <double> cr3a ( 3, 4 );
   complex <double> cr3b ( 5,0 );

   cout << "The 1st left-side complex number is cl3a = " << cl3a << endl;
   cout << "The 1st right-side complex number is cr3a = " << cr3a << endl;
   if ( cl3a != cr3a )
      cout << "The complex numbers cl3a & cr3a are not equal." << endl;
   else
      cout << "The complex numbers cl3a & cr3a are equal." << endl;

   cout << "The 2nd left-side complex number is cl3b = " << cl3b << endl;
   cout << "The 2nd right-side complex number is cr3b = " << cr3b << endl;
   if ( cl3b != cr3b )
      cout << "The complex numbers cl3b & cr3b are not equal." << endl;
   else
      cout << "The complex numbers cl3b & cr3b are equal." << endl;
   cout << endl;
}

The left-side complex number is cl1 = (2.59808,1.5)
The 1st right-side complex number is cr1a = (2.59808,1.5)
The 2nd right-side complex number is cr1b = (1,1.73205)
The complex numbers cl1 & cr1a are equal.
The complex numbers cl1 & cr1b are not equal.

The 1st left-side complex number is cl2a = (3,4)
The 1st right-side complex number is cr2a = 3
The complex numbers cl2a & cr2a are not equal.
The 2nd left-side complex number is cl2b = (5,0)
The 2nd right-side complex number is cr2b = 5
The complex numbers cl2b & cr2b are equal.

The 1st left-side complex number is cl3a = 3
The 1st right-side complex number is cr3a = (3,4)
The complex numbers cl3a & cr3a are not equal.
The 2nd left-side complex number is cl3b = 5
The 2nd right-side complex number is cr3b = (5,0)
The complex numbers cl3b & cr3b are equal.

operator*

将两个复数相乘，这两个复数或其中一个可能属于其类型与实部和虚部的类型相同的子集。

template <class Type>
complex<Type> operator*(
    const complex<Type>& left,
    const complex<Type>& right);

template <class Type>
complex<Type> operator*(
    const complex<Type>& left,
    const Type& right);

template <class Type>
complex<Type> operator*(
    const Type& left,
    const complex<Type>& right);

参数

left
两个复数的第一个数或属于复数参数类型的数通过 * 运算相乘。

right
两个复数的第二个数或属于复数参数类型的数通过 * 运算相乘。

返回值

由两个数相乘得出的结果的复数的值和类型由参数输入指定。

备注

重载该操作，以执行简单的算术运算，而无需将数据转换为特定格式。

示例

// complex_op_mult.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Example of the first member function
   // type complex<double> times type complex<double>
   complex <double> cl1 ( polar (3.0, pi / 6 ) );
   complex <double> cr1 ( polar (2.0, pi / 3 ) );
   complex <double> cs1 = cl1 * cr1;

   cout << "The left-side complex number is cl1 = " << cl1 << endl;
   cout << "The right-side complex number is cr1 = " << cr1 << endl;
   cout << "Product of two complex numbers is: cs1 = " << cs1 << endl;
   double abscs1 = abs ( cs1 );
   double argcs1 = arg ( cs1 );
   cout << "The modulus of cs1 is: " << abscs1 << endl;
   cout << "The argument of cs1 is: "<< argcs1 << " radians, which is "
        << argcs1 * 180 / pi << " degrees." << endl << endl;

   // Example of the second member function
   // type complex<double> times type double
   complex <double> cl2 ( polar ( 3.0, pi / 6 ) );
   double cr2 =5;
   complex <double> cs2 = cl2 * cr2;

   cout << "The left-side complex number is cl2 = " << cl2 << endl;
   cout << "The right-side complex number is cr2 = " << cr2 << endl;
   cout << "Product of two complex numbers is: cs2 = " << cs2 << endl;
   double abscs2 = abs ( cs2 );
   double argcs2 = arg ( cs2 );
   cout << "The modulus of cs2 is: " << abscs2 << endl;
   cout << "The argument of cs2 is: "<< argcs2 << " radians, which is "
        << argcs2 * 180 / pi << " degrees." << endl << endl;

   // Example of the third member function
   // type double times type complex<double>
   double cl3 = 5;
   complex <double> cr3 ( polar (3.0, pi / 6 ) );
   complex <double> cs3 = cl3 * cr3;

   cout << "The left-side complex number is cl3 = " << cl3 << endl;
   cout << "The right-side complex number is cr3 = " << cr3 << endl;
   cout << "Product of two complex numbers is: cs3 = " << cs3 << endl;
   double abscs3 = abs ( cs3 );
   double argcs3 = arg ( cs3 );
   cout << "The modulus of cs3 is: " << abscs3 << endl;
   cout << "The argument of cs3 is: "<< argcs3 << " radians, which is "
        << argcs3 * 180 / pi << " degrees." << endl << endl;
}

operator+

将两个复数相加，这两个复数或其中一个可能属于其类型与实部和虚部的类型相同的子集。

template <class Type>
complex<Type> operator+(
    const complex<Type>& left,
    const complex<Type>& right);

template <class Type>
complex<Type> operator+(
    const complex<Type>& left,
    const Type& right);

template <class Type>
complex<Type> operator+(
    const Type& left,
    const complex<Type>& right);

template <class Type>
complex<Type> operator+(const complex<Type>& left);

参数

left
两个复数的第一个数或属于复数参数类型的数通过 + 运算相加。

right
两个复数的第二个数或属于复数参数类型的数通过 + 运算相加。

返回值

由两个数相加得出的复数的值和类型由参数输入指定。

注解

重载该操作，以执行简单的算术运算，而无需将数据转换为特定格式。 一元运算符返回 left。

示例

// complex_op_add.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Example of the first member function
   // type complex<double> plus type complex<double>
   complex <double> cl1 ( 3.0, 4.0 );
   complex <double> cr1 ( 2.0, 5.0 );
   complex <double> cs1 = cl1 + cr1;

   cout << "The left-side complex number is cl1 = " << cl1 << endl;
   cout << "The right-side complex number is cr1 = " << cr1 << endl;
   cout << "The sum of the two complex numbers is: cs1 = " << cs1 << endl;
   double abscs1 = abs ( cs1 );
   double argcs1 = arg ( cs1 );
   cout << "The modulus of cs1 is: " << abscs1 << endl;
   cout << "The argument of cs1 is: "<< argcs1 << " radians, which is "
        << argcs1 * 180 / pi << " degrees." << endl << endl;

   // Example of the second member function
   // type complex<double> plus type double
   complex <double> cl2 ( 3.0, 4.0 );
   double cr2 =5.0;
   complex <double> cs2 = cl2 + cr2;

   cout << "The left-side complex number is cl2 = " << cl2 << endl;
   cout << "The right-side complex number is cr2 = " << cr2 << endl;
   cout << "The sum of the two complex numbers is: cs2 = " << cs2 << endl;
   double abscs2 = abs ( cs2 );
   double argcs2 = arg ( cs2 );
   cout << "The modulus of cs2 is: " << abscs2 << endl;
   cout << "The argument of cs2 is: "<< argcs2 << " radians, which is "
        << argcs2 * 180 / pi << " degrees." << endl << endl;

   // Example of the third member function
   // type double plus type complex<double>
   double cl3 = 5.0;
   complex <double> cr3 ( 3.0, 4.0 );
   complex <double> cs3 = cl3 + cr3;

   cout << "The left-side complex number is cl3 = " << cl3 << endl;
   cout << "The right-side complex number is cr3 = " << cr3 << endl;
   cout << "The sum of the two complex numbers is: cs3 = " << cs3 << endl;
   double abscs3 = abs ( cs3 );
   double argcs3 = arg ( cs3 );
   cout << "The modulus of cs3 is: " << abscs3 << endl;
   cout << "The argument of cs3 is: "<< argcs3 << " radians, which is "
        << argcs3 * 180 / pi << " degrees." << endl << endl;

   // Example of the fourth member function
   // plus type complex<double>
   complex <double> cr4 ( 3.0, 4.0 );
   complex <double> cs4 = + cr4;

   cout << "The right-side complex number is cr4 = " << cr4 << endl;
   cout << "The result of the unary application of + to the right-side"
        << "\n complex number is: cs4 = " << cs4 << endl;
   double abscs4 = abs ( cs4 );
   double argcs4 = arg ( cs4 );
   cout << "The modulus of cs4 is: " << abscs4 << endl;
   cout << "The argument of cs4 is: "<< argcs4 << " radians, which is "
        << argcs4 * 180 / pi << " degrees." << endl << endl;
}

The left-side complex number is cl1 = (3,4)
The right-side complex number is cr1 = (2,5)
The sum of the two complex numbers is: cs1 = (5,9)
The modulus of cs1 is: 10.2956
The argument of cs1 is: 1.0637 radians, which is 60.9454 degrees.

The left-side complex number is cl2 = (3,4)
The right-side complex number is cr2 = 5
The sum of the two complex numbers is: cs2 = (8,4)
The modulus of cs2 is: 8.94427
The argument of cs2 is: 0.463648 radians, which is 26.5651 degrees.

The left-side complex number is cl3 = 5
The right-side complex number is cr3 = (3,4)
The sum of the two complex numbers is: cs3 = (8,4)
The modulus of cs3 is: 8.94427
The argument of cs3 is: 0.463648 radians, which is 26.5651 degrees.

The right-side complex number is cr4 = (3,4)
The result of the unary application of + to the right-side
complex number is: cs4 = (3,4)
The modulus of cs4 is: 5
The argument of cs4 is: 0.927295 radians, which is 53.1301 degrees.

operator-

将两个复数相减，这两个复数或其中一个可能属于其类型与实部和虚部的类型相同的子集。

template <class Type>
complex<Type> operator-(
    const complex<Type>& left,
    const complex<Type>& right);

template <class Type>
complex<Type> operator-(
    const complex<Type>& left,
    const Type& right);

template <class Type>
complex<Type> operator-(
    const Type& left,
    const complex<Type>& right);

template <class Type>
complex<Type> operator-(const complex<Type>& left);

参数

left
两个复数的第一个数或属于复数参数类型的数通过 - 运算相减。

right
两个复数的第二个数或属于复数参数类型的数通过 - 运算相减。

返回值

由 right 从 left 减去得出的复数，两个数的值由参数输入指定。

备注

重载该操作，以执行简单的算术运算，而无需将数据转换为特定格式。

一元运算符更改复数的符号并返回一个值，其实部是数字输入实部的负值，其虚部是数字输入虚部的负值。

示例

// complex_op_sub.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Example of the first member function
   // type complex<double> minus type complex<double>
   complex <double> cl1 ( 3.0, 4.0 );
   complex <double> cr1 ( 2.0, 5.0 );
   complex <double> cs1 = cl1 - cr1;

   cout << "The left-side complex number is cl1 = " << cl1 << endl;
   cout << "The right-side complex number is cr1 = " << cr1 << endl;
   cout << "Difference of two complex numbers is: cs1 = " << cs1 << endl;
   double abscs1 = abs ( cs1 );
   double argcs1 = arg ( cs1 );
   cout << "The modulus of cs1 is: " << abscs1 << endl;
   cout << "The argument of cs1 is: "<< argcs1 << " radians, which is "
        << argcs1 * 180 / pi << " degrees." << endl << endl;

   // Example of the second member function
   // type complex<double> minus type double
   complex <double> cl2 ( 3.0, 4.0 );
   double cr2 =5.0;
   complex <double> cs2 = cl2 - cr2;

   cout << "The left-side complex number is cl2 = " << cl2 << endl;
   cout << "The right-side complex number is cr2 = " << cr2 << endl;
   cout << "Difference of two complex numbers is: cs2 = " << cs2 << endl;
   double abscs2 = abs ( cs2 );
   double argcs2 = arg ( cs2 );
   cout << "The modulus of cs2 is: " << abscs2 << endl;
   cout << "The argument of cs2 is: "<< argcs2 << " radians, which is "
        << argcs2 * 180 / pi << " degrees." << endl << endl;

   // Example of the third member function
   // type double minus type complex<double>
   double cl3 = 5.0;
   complex <double> cr3 ( 3.0, 4.0 );
   complex <double> cs3 = cl3 - cr3;

   cout << "The left-side complex number is cl3 = " << cl3 << endl;
   cout << "The right-side complex number is cr3 = " << cr3 << endl;
   cout << "Difference of two complex numbers is: cs3 = " << cs3 << endl;
   double abscs3 = abs ( cs3 );
   double argcs3 = arg ( cs3 );
   cout << "The modulus of cs3 is: " << abscs3 << endl;
   cout << "The argument of cs3 is: "<< argcs3 << " radians, which is "
        << argcs3 * 180 / pi << " degrees." << endl << endl;

   // Example of the fourth member function
   // minus type complex<double>
   complex <double> cr4 ( 3.0, 4.0 );
   complex <double> cs4 = - cr4;

   cout << "The right-side complex number is cr4 = " << cr4 << endl;
   cout << "The result of the unary application of - to the right-side"
        << "\n complex number is: cs4 = " << cs4 << endl;
   double abscs4 = abs ( cs4 );
   double argcs4 = arg ( cs4 );
   cout << "The modulus of cs4 is: " << abscs4 << endl;
   cout << "The argument of cs4 is: "<< argcs4 << " radians, which is "
        << argcs4 * 180 / pi << " degrees." << endl << endl;
}

The left-side complex number is cl1 = (3,4)
The right-side complex number is cr1 = (2,5)
Difference of two complex numbers is: cs1 = (1,-1)
The modulus of cs1 is: 1.41421
The argument of cs1 is: -0.785398 radians, which is -45 degrees.

The left-side complex number is cl2 = (3,4)
The right-side complex number is cr2 = 5
Difference of two complex numbers is: cs2 = (-2,4)
The modulus of cs2 is: 4.47214
The argument of cs2 is: 2.03444 radians, which is 116.565 degrees.

The left-side complex number is cl3 = 5
The right-side complex number is cr3 = (3,4)
Difference of two complex numbers is: cs3 = (2,-4)
The modulus of cs3 is: 4.47214
The argument of cs3 is: -1.10715 radians, which is -63.4349 degrees.

The right-side complex number is cr4 = (3,4)
The result of the unary application of - to the right-side
complex number is: cs4 = (-3,-4)
The modulus of cs4 is: 5
The argument of cs4 is: -2.2143 radians, which is -126.87 degrees.

operator/

将两个复数相除，这两个复数或其中一个可能属于其类型与实部和虚部的类型相同的子集。

template <class Type>
complex<Type> operator*(
    const complex<Type>& left,
    const complex<Type>& right);

template <class Type>
complex<Type> operator*(
    const complex<Type>& left,
    const Type& right);

template <class Type>
complex<Type> operator*(
    const Type& left,
    const complex<Type>& right);

参数

left
复数或属于复数参数类型的数通过 / 运算用分子除以分母。

right
复数或属于复数参数类型的数通过 / 运算用分子除以分母。

返回值

用分子除以分母得出的复数的值由参数输入指定。

备注

重载该操作，以执行简单的算术运算，而无需将数据转换为特定格式。

示例

// complex_op_div.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Example of the first member function
   // type complex<double> divided by type complex<double>
   complex <double> cl1 ( polar ( 3.0, pi / 6 ) );
   complex <double> cr1 ( polar ( 2.0, pi / 3 ) );
   complex <double> cs1 = cl1 / cr1;

   cout << "The left-side complex number is cl1 = " << cl1 << endl;
   cout << "The right-side complex number is cr1 = " << cr1 << endl;
   cout << "The quotient of the two complex numbers is: cs1 = cl1 /cr1 = "
        << cs1 << endl;
   double abscs1 = abs ( cs1 );
   double argcs1 = arg ( cs1 );
   cout << "The modulus of cs1 is: " << abscs1 << endl;
   cout << "The argument of cs1 is: "<< argcs1 << " radians, which is "
        << argcs1 * 180 / pi << " degrees." << endl << endl;

   // example of the second member function
   // type complex<double> divided by type double
   complex <double> cl2 ( polar (3.0, pi / 6 ) );
   double cr2 =5;
   complex <double> cs2 = cl2 / cr2;

   cout << "The left-side complex number is cl2 = " << cl2 << endl;
   cout << "The right-side complex number is cr2 = " << cr2 << endl;
   cout << "The quotient of the two complex numbers is: cs2 = cl2 /cr2 = "
        << cs2 << endl;
   double abscs2 = abs ( cs2 );
   double argcs2 = arg ( cs2 );
   cout << "The modulus of cs2 is: " << abscs2 << endl;
   cout << "The argument of cs2 is: "<< argcs2 << " radians, which is "
        << argcs2 * 180 / pi << " degrees." << endl << endl;

   // Example of the third member function
   // type double divided by type complex<double>
   double cl3 = 5;
   complex <double> cr3 ( polar ( 3.0, pi / 6 ) );
   complex <double> cs3 = cl3 / cr3;

   cout << "The left-side complex number is cl3 = " << cl3 << endl;
   cout << "The right-side complex number is cr3 = " << cr3 << endl;
   cout << "The quotient of the two complex numbers is: cs3 = cl3 /cr2 = "
        << cs3 << endl;
   double abscs3 = abs ( cs3 );
   double argcs3 = arg ( cs3 );
   cout << "The modulus of cs3 is: " << abscs3 << endl;
   cout << "The argument of cs3 is: "<< argcs3 << " radians, which is "
        << argcs3 * 180 / pi << " degrees." << endl << endl;
}

The left-side complex number is cl1 = (2.59808,1.5)
The right-side complex number is cr1 = (1,1.73205)
The quotient of the two complex numbers is: cs1 = cl1 /cr1 = (1.29904,-0.75)
The modulus of cs1 is: 1.5
The argument of cs1 is: -0.523599 radians, which is -30 degrees.

The left-side complex number is cl2 = (2.59808,1.5)
The right-side complex number is cr2 = 5
The quotient of the two complex numbers is: cs2 = cl2 /cr2 = (0.519615,0.3)
The modulus of cs2 is: 0.6
The argument of cs2 is: 0.523599 radians, which is 30 degrees.

The left-side complex number is cl3 = 5
The right-side complex number is cr3 = (2.59808,1.5)
The quotient of the two complex numbers is: cs3 = cl3 /cr2 = (1.44338,-0.833333)
The modulus of cs3 is: 1.66667
The argument of cs3 is: -0.523599 radians, which is -30 degrees.

operator<<

向输出流插入指定的复数。

template <class Type, class Elem, class Traits>
basic_ostream<Elem, Traits>& operator<<(
    basic_ostream<Elem, Traits>& Ostr,
    const complex<Type>& right);

参数

Ostr
要输入到输出流的复数。

right
要输入到输出流的复数。

返回值

采用笛卡尔坐标格式：（实部、虚部），将指定复数值写入 Ostr。

注解

对输出流进行重载，以使其接受任何形式的复数，且其默认输出格式为笛卡尔坐标格式。

示例

// complex_op_insert.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   complex <double> c1 ( 3.0, 4.0 );
   cout << "Complex number c1 = " << c1 << endl;

   complex <double> c2  ( polar ( 2.0, pi / 6 ) );
   cout << "Complex number c2 = " << c2 << endl;

   // To display in polar form
   double absc2 = abs ( c2 );
   double argc2 = arg ( c2 );
   cout << "The modulus of c2 is: " << absc2 << endl;
   cout << "The argument of c2 is: "<< argc2 << " radians, which is "
        << argc2 * 180 / pi << " degrees." << endl << endl;
}

Complex number c1 = (3,4)
Complex number c2 = (1.73205,1)
The modulus of c2 is: 2
The argument of c2 is: 0.523599 radians, which is 30 degrees.

operator==

测试两个复数是否相等，这两个复数或其中一个可能属于其类型与实部和虚部的类型相同的子集。

template <class Type>
bool operator==(
    const complex<Type>& left,
    const complex<Type>& right);

template <class Type>
bool operator==(
    const complex<Type>& left,
    const Type& right);

template <class Type>
bool operator==(
    const Type& left,
    const complex<Type>& right);

参数

left
将测试其不等性的复数或与复数的参数类型相同的对象。

right
将测试其不等性的复数或与复数的参数类型相同的对象。

返回值

如果数字相等，则为 true；如果数字不相等，则为 false。

注解

当且仅当实部和虚部都相等时，两个复数才相等。 否则，它们不相等。

重载该操作，以便可以执行比较测试，而无需将数据转换为特定格式。

示例

// complex_op_EQ.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   // Example of the first member function
   // type complex<double> compared with type complex<double>
   complex <double> cl1 ( polar ( 3.0, pi / 6 ) );
   complex <double> cr1a ( polar ( 3.0, pi /6 ) );
   complex <double> cr1b ( polar ( 2.0, pi / 3 ) );

   cout << "The left-side complex number is cl1 = " << cl1 << endl;
   cout << "The 1st right-side complex number is cr1a = " << cr1a << endl;
   cout << "The 2nd right-side complex number is cr1b = " << cr1b << endl;
   if ( cl1 == cr1a )
      cout << "The complex numbers cl1 & cr1a are equal." << endl;
   else
      cout << "The complex numbers cl1 & cr1a are not equal." << endl;
   if ( cl1 == cr1b )
      cout << "The complex numbers cl1 & cr1b are equal." << endl;
   else
      cout << "The complex numbers cl1 & cr1b are not equal." << endl;
   cout << endl;

   // Example of the second member function
   // type complex<int> compared with type int
   complex <int> cl2a ( 3, 4 );
   complex <int> cl2b ( 5,0 );
   int cr2a =3;
   int cr2b =5;

   cout << "The 1st left-side complex number is cl2a = " << cl2a << endl;
   cout << "The 1st right-side complex number is cr2a = " << cr2a << endl;
   if ( cl2a == cr2a )
      cout << "The complex numbers cl2a & cr2a are equal." << endl;
   else
      cout << "The complex numbers cl2a & cr2a are not equal." << endl;

   cout << "The 2nd left-side complex number is cl2b = " << cl2b << endl;
   cout << "The 2nd right-side complex number is cr2b = " << cr2b << endl;
   if ( cl2b == cr2b )
      cout << "The complex numbers cl2b & cr2b are equal." << endl;
   else
      cout << "The complex numbers cl2b & cr2b are not equal." << endl;
   cout << endl;

   // Example of the third member function
   // type double compared with type complex<double>
   double cl3a =3;
   double cl3b =5;
   complex <double> cr3a (3, 4 );
   complex <double> cr3b (5,0 );

   cout << "The 1st left-side complex number is cl3a = " << cl3a << endl;
   cout << "The 1st right-side complex number is cr3a = " << cr3a << endl;
   if ( cl3a == cr3a )
      cout << "The complex numbers cl3a & cr3a are equal." << endl;
   else
      cout << "The complex numbers cl3a & cr3a are not equal." << endl;

   cout << "The 2nd left-side complex number is cl3b = " << cl3b << endl;
   cout << "The 2nd right-side complex number is cr3b = " << cr3b << endl;
   if ( cl3b == cr3b )
      cout << "The complex numbers cl3b & cr3b are equal." << endl;
   else
      cout << "The complex numbers cl3b & cr3b are not equal." << endl;
   cout << endl;
}

The left-side complex number is cl1 = (2.59808,1.5)
The 1st right-side complex number is cr1a = (2.59808,1.5)
The 2nd right-side complex number is cr1b = (1,1.73205)
The complex numbers cl1 & cr1a are equal.
The complex numbers cl1 & cr1b are not equal.

The 1st left-side complex number is cl2a = (3,4)
The 1st right-side complex number is cr2a = 3
The complex numbers cl2a & cr2a are not equal.
The 2nd left-side complex number is cl2b = (5,0)
The 2nd right-side complex number is cr2b = 5
The complex numbers cl2b & cr2b are equal.

The 1st left-side complex number is cl3a = 3
The 1st right-side complex number is cr3a = (3,4)
The complex numbers cl3a & cr3a are not equal.
The 2nd left-side complex number is cl3b = 5
The 2nd right-side complex number is cr3b = (5,0)
The complex numbers cl3b & cr3b are equal.

operator>>

从输入流提取一个复值。

template <class Type, class Elem, class Traits>
basic_istream<Elem, Traits>& operator>>(
   basic_istream<Elem, Traits>& Istr,
   complex<Type>& right);

参数

Istr
要从中提取复数的输入流。

right
正在从输入流提取的复数。

返回值

从 Istr 读取指定的复数，并返回到 right。

注解

有效的输入格式为

  • （实部、虚部）

  • （实部）

  • 实部

示例

// complex_op_extract.cpp
// compile with: /EHsc
#include <complex>
#include <iostream>

int main( )
{
   using namespace std;
   double pi = 3.14159265359;

   complex <double> c2;

   cout << "Input a complex number ( try: 2.0 ): ";
   cin >> c2;
   cout << c2 << endl;
}

Input a complex number ( try: 2.0 ): 2.0
2.0