RelationalStrings.DuplicateIndexUniquenessMismatch 方法
定义
重要
一些信息与预发行产品相关,相应产品在发行之前可能会进行重大修改。 对于此处提供的信息,Microsoft 不作任何明示或暗示的担保。
“{entityType1}”上的索引 {index1} 和 “{entityType2}” 上的 {index2} 都映射到“{table}”。{indexName}“,但具有不同的唯一性配置。
public static string DuplicateIndexUniquenessMismatch (object index1, object entityType1, object index2, object entityType2, object table, object indexName);
public static string DuplicateIndexUniquenessMismatch (object indexProperties1, object entityType1, object indexProperties2, object entityType2, object table, object indexName);
public static string DuplicateIndexUniquenessMismatch (object? indexProperties1, object? entityType1, object? indexProperties2, object? entityType2, object? table, object? indexName);
public static string DuplicateIndexUniquenessMismatch (object? index1, object? entityType1, object? index2, object? entityType2, object? table, object? indexName);
static member DuplicateIndexUniquenessMismatch : obj * obj * obj * obj * obj * obj -> string
static member DuplicateIndexUniquenessMismatch : obj * obj * obj * obj * obj * obj -> string
Public Shared Function DuplicateIndexUniquenessMismatch (index1 As Object, entityType1 As Object, index2 As Object, entityType2 As Object, table As Object, indexName As Object) As String
Public Shared Function DuplicateIndexUniquenessMismatch (indexProperties1 As Object, entityType1 As Object, indexProperties2 As Object, entityType2 As Object, table As Object, indexName As Object) As String
参数
- index1indexProperties1
- Object
- entityType1
- Object
- index2indexProperties2
- Object
- entityType2
- Object
- table
- Object
- indexName
- Object
返回
适用于
反馈
https://aka.ms/ContentUserFeedback。
即将发布:在整个 2024 年,我们将逐步淘汰作为内容反馈机制的“GitHub 问题”,并将其取代为新的反馈系统。 有关详细信息,请参阅:提交和查看相关反馈