JulianCalendar.AddYears(DateTime, Int32) 方法

定义

返回与指定 DateTime 相距指定年数的 DateTime

public:
 override DateTime AddYears(DateTime time, int years);
public override DateTime AddYears (DateTime time, int years);
override this.AddYears : DateTime * int -> DateTime
Public Overrides Function AddYears (time As DateTime, years As Integer) As DateTime

参数

time
DateTime

将向其添加年数的 DateTime

years
Int32

要添加的年数。

返回

将指定年数添加到指定的 DateTime 中时得到的 DateTime

例外

生成的 DateTime 超出了支持的范围。

示例

下面的代码示例以 Julian 日历形式显示 的 DateTime 多个组件的值。

using namespace System;
using namespace System::Globalization;
void DisplayValues( Calendar^ myCal, DateTime myDT )
{
   Console::WriteLine( "   Era:        {0}", myCal->GetEra( myDT ) );
   Console::WriteLine( "   Year:       {0}", myCal->GetYear( myDT ) );
   Console::WriteLine( "   Month:      {0}", myCal->GetMonth( myDT ) );
   Console::WriteLine( "   DayOfYear:  {0}", myCal->GetDayOfYear( myDT ) );
   Console::WriteLine( "   DayOfMonth: {0}", myCal->GetDayOfMonth( myDT ) );
   Console::WriteLine( "   DayOfWeek:  {0}", myCal->GetDayOfWeek( myDT ) );
   Console::WriteLine();
}

int main()
{
   
   // Sets a DateTime to April 3, 2002 of the Gregorian calendar.
   DateTime myDT = DateTime(2002,4,3,gcnew GregorianCalendar);
   
   // Creates an instance of the JulianCalendar.
   JulianCalendar^ myCal = gcnew JulianCalendar;
   
   // Displays the values of the DateTime.
   Console::WriteLine( "April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:" );
   DisplayValues( myCal, myDT );
   
   // Adds two years and ten months.
   myDT = myCal->AddYears( myDT, 2 );
   myDT = myCal->AddMonths( myDT, 10 );
   
   // Displays the values of the DateTime.
   Console::WriteLine( "After adding two years and ten months:" );
   DisplayValues( myCal, myDT );
}

/*
This code produces the following output.

April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:
   Era:        1
   Year:       2002
   Month:      3
   DayOfYear:  80
   DayOfMonth: 21
   DayOfWeek:  Wednesday

After adding two years and ten months:
   Era:        1
   Year:       2005
   Month:      1
   DayOfYear:  21
   DayOfMonth: 21
   DayOfWeek:  Thursday

*/
using System;
using System.Globalization;

public class SamplesJulianCalendar  {

   public static void Main()  {

      // Sets a DateTime to April 3, 2002 of the Gregorian calendar.
      DateTime myDT = new DateTime( 2002, 4, 3, new GregorianCalendar() );

      // Creates an instance of the JulianCalendar.
      JulianCalendar myCal = new JulianCalendar();

      // Displays the values of the DateTime.
      Console.WriteLine( "April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:" );
      DisplayValues( myCal, myDT );

      // Adds two years and ten months.
      myDT = myCal.AddYears( myDT, 2 );
      myDT = myCal.AddMonths( myDT, 10 );

      // Displays the values of the DateTime.
      Console.WriteLine( "After adding two years and ten months:" );
      DisplayValues( myCal, myDT );
   }

   public static void DisplayValues( Calendar myCal, DateTime myDT )  {
      Console.WriteLine( "   Era:        {0}", myCal.GetEra( myDT ) );
      Console.WriteLine( "   Year:       {0}", myCal.GetYear( myDT ) );
      Console.WriteLine( "   Month:      {0}", myCal.GetMonth( myDT ) );
      Console.WriteLine( "   DayOfYear:  {0}", myCal.GetDayOfYear( myDT ) );
      Console.WriteLine( "   DayOfMonth: {0}", myCal.GetDayOfMonth( myDT ) );
      Console.WriteLine( "   DayOfWeek:  {0}", myCal.GetDayOfWeek( myDT ) );
      Console.WriteLine();
   }
}

/*
This code produces the following output.

April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:
   Era:        1
   Year:       2002
   Month:      3
   DayOfYear:  80
   DayOfMonth: 21
   DayOfWeek:  Wednesday

After adding two years and ten months:
   Era:        1
   Year:       2005
   Month:      1
   DayOfYear:  21
   DayOfMonth: 21
   DayOfWeek:  Thursday

*/
Imports System.Globalization


Public Class SamplesJulianCalendar   

   Public Shared Sub Main()

      ' Sets a DateTime to April 3, 2002 of the Gregorian calendar.
      Dim myDT As New DateTime(2002, 4, 3, New GregorianCalendar())

      ' Creates an instance of the JulianCalendar.
      Dim myCal As New JulianCalendar()

      ' Displays the values of the DateTime.
      Console.WriteLine("April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:")
      DisplayValues(myCal, myDT)

      ' Adds two years and ten months.
      myDT = myCal.AddYears(myDT, 2)
      myDT = myCal.AddMonths(myDT, 10)

      ' Displays the values of the DateTime.
      Console.WriteLine("After adding two years and ten months:")
      DisplayValues(myCal, myDT)

   End Sub

   Public Shared Sub DisplayValues(myCal As Calendar, myDT As DateTime)
      Console.WriteLine("   Era:        {0}", myCal.GetEra(myDT))
      Console.WriteLine("   Year:       {0}", myCal.GetYear(myDT))
      Console.WriteLine("   Month:      {0}", myCal.GetMonth(myDT))
      Console.WriteLine("   DayOfYear:  {0}", myCal.GetDayOfYear(myDT))
      Console.WriteLine("   DayOfMonth: {0}", myCal.GetDayOfMonth(myDT))
      Console.WriteLine("   DayOfWeek:  {0}", myCal.GetDayOfWeek(myDT))
      Console.WriteLine()
   End Sub

End Class


'This code produces the following output.
'
'April 3, 2002 of the Gregorian calendar equals the following in the Julian calendar:
'   Era:        1
'   Year:       2002
'   Month:      3
'   DayOfYear:  80
'   DayOfMonth: 21
'   DayOfWeek:  Wednesday
'
'After adding two years and ten months:
'   Era:        1
'   Year:       2005
'   Month:      1
'   DayOfYear:  21
'   DayOfMonth: 21
'   DayOfWeek:  Thursday

注解

如果生成的日期不是结果 DateTime 年份的月中的有效日期,则结果的日期部分将受到影响。 它更改为结果年份中结果月份的最后一个有效日期。 生成的 DateTime 月份部分与指定的 DateTime保持相同。 此实现仅支持当前时代。 因此, ArgumentException 如果生成的年份在指定的 DateTime的纪元之外,则引发 。 生成的 DateTime 的一天中的时间部分与指定的 DateTime保持相同。

例如,2 月有 28 天,但闰年有 29 天除外。 如果指定日期是闰年 2 月 29 日,值为 years 1,则生成的日期为下一年 2 月的第 28 天。

如果 years 为负值,则生成的 DateTime 早于指定的 DateTime

Kind返回DateTime的值的 属性始终等于 DateTimeKind.Unspecified。 可以通过调用 DateTime.SpecifyKind 方法保留 Kind 参数的 time 属性,如以下示例所示。

returnTime = DateTime.SpecifyKind(cal.AddYears(time, years), time.Kind);
returnTime = DateTime.SpecifyKind(cal.AddYears(time, years), time.Kind)

适用于

另请参阅