DiscoveryMessageSequence.Inequality 运算符

定义

命名空间:

System.ServiceModel.Discovery

程序集:

System.ServiceModel.Discovery.dll

确定 DiscoveryMessageSequence 的两个指定实例是否不相等。

public:
 static bool operator !=(System::ServiceModel::Discovery::DiscoveryMessageSequence ^ messageSequence1, System::ServiceModel::Discovery::DiscoveryMessageSequence ^ messageSequence2);

public static bool operator != (System.ServiceModel.Discovery.DiscoveryMessageSequence messageSequence1, System.ServiceModel.Discovery.DiscoveryMessageSequence messageSequence2);

static member op_Inequality : System.ServiceModel.Discovery.DiscoveryMessageSequence * System.ServiceModel.Discovery.DiscoveryMessageSequence -> bool

Public Shared Operator != (messageSequence1 As DiscoveryMessageSequence, messageSequence2 As DiscoveryMessageSequence) As Boolean

参数

messageSequence1

DiscoveryMessageSequence

发现消息序列。

messageSequence2

DiscoveryMessageSequence

发现消息序列。

返回

Boolean

如果两个发现消息序列实例不相等，则为 true；否则为 false。