BatchedJoinBlock<T1,T2,T3>.TryReceiveAll 方法

定义

命名空间:

System.Threading.Tasks.Dataflow

程序集:

System.Threading.Tasks.Dataflow.dll

从 IReceivableSourceBlock<TOutput> 中尝试同步接收所有可用项。

public:
 virtual bool TryReceiveAll([Runtime::InteropServices::Out] System::Collections::Generic::IList<Tuple<System::Collections::Generic::IList<T1> ^, System::Collections::Generic::IList<T2> ^, System::Collections::Generic::IList<T3> ^> ^> ^ % items);

public bool TryReceiveAll (out System.Collections.Generic.IList<Tuple<System.Collections.Generic.IList<T1>,System.Collections.Generic.IList<T2>,System.Collections.Generic.IList<T3>>> items);

public bool TryReceiveAll (out System.Collections.Generic.IList<Tuple<System.Collections.Generic.IList<T1>,System.Collections.Generic.IList<T2>,System.Collections.Generic.IList<T3>>>? items);

abstract member TryReceiveAll : IList -> bool
override this.TryReceiveAll : IList -> bool

Public Function TryReceiveAll (ByRef items As IList(Of Tuple(Of IList(Of T1), IList(Of T2), IList(Of T3)))) As Boolean

参数

items

IList<Tuple<IList<T1>,IList<T2>,IList<T3>>>

从源中接收的项。

返回

Boolean

如果可以接收一个或多个项目，则为 true；否则为 false。

注解

此方法不会阻止等待源提供项。

它将在检查元素后返回，无论元素是否可用。