Uri.HexEscape(Char) 方法

定义

命名空间:

System

程序集:

System.Runtime.dll

Source:

Uri.cs

将指定的字符转换为它的等效十六进制字符。

public:
 static System::String ^ HexEscape(char character);

public static string HexEscape (char character);

static member HexEscape : char -> string

Public Shared Function HexEscape (character As Char) As String

参数

character

Char

要转换为十六进制表示形式的字符。

返回

String

指定字符的十六进制表示形式。

例外

ArgumentOutOfRangeException

character 大于 255。

示例

以下示例将字符转换为其十六进制等效项，并将其写入控制台。

char testChar = 'e';
if ( Uri::IsHexDigit( testChar ) == true )
{
   Console::WriteLine( "'{0}' is the hexadecimal representation of {1}",
      testChar, Uri::FromHex( testChar ) );
}
else
{
   Console::WriteLine( "'{0}' is not a hex character", testChar );
}

String^ returnString = Uri::HexEscape( testChar );
Console::WriteLine( "The hexadecimal value of '{0}' is {1}", testChar, returnString );

char  testChar = 'e';
if (Uri.IsHexDigit(testChar) == true)
    Console.WriteLine("'{0}' is the hexadecimal representation of {1}", testChar, Uri.FromHex(testChar));
else
    Console.WriteLine("'{0}' is not a hexadecimal character", testChar);

string returnString = Uri.HexEscape(testChar);
Console.WriteLine("The hexadecimal value of '{0}' is {1}", testChar, returnString);

let testChar = 'e'
if Uri.IsHexDigit testChar then
    printfn $"'{testChar}' is the hexadecimal representation of {Uri.FromHex testChar}"
else
    printfn $"'{testChar}' is not a hexadecimal character"

let returnString = Uri.HexEscape testChar
printfn $"The hexadecimal value of '{testChar}' is {returnString}"

Dim testChar As Char = "e"c
If Uri.IsHexDigit(testChar) = True Then
    Console.WriteLine("'{0}' is the hexadecimal representation of {1}", testChar, Uri.FromHex(testChar))
Else
    Console.WriteLine("'{0}' is not a hexadecimal character", testChar)
End If 
Dim returnString As String = Uri.HexEscape(testChar)
Console.WriteLine("The hexadecimal value of '{0}' is {1}", testChar, returnString)