Uri.IsHexDigit(Char) 方法
定义
重要
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确定指定的字符是否为有效的十六进制数字。
public:
static bool IsHexDigit(char character);
public static bool IsHexDigit (char character);
static member IsHexDigit : char -> bool
Public Shared Function IsHexDigit (character As Char) As Boolean
参数
- character
- Char
要验证的字符。
返回
如果字符是有效的十六进制数字,则为 true
;否则为 false
。
示例
以下示例确定字符是否为十六进制字符,如果为,则向控制台写入相应的十进制值。
char testChar = 'e';
if ( Uri::IsHexDigit( testChar ) == true )
{
Console::WriteLine( "'{0}' is the hexadecimal representation of {1}",
testChar, Uri::FromHex( testChar ) );
}
else
{
Console::WriteLine( "'{0}' is not a hex character", testChar );
}
String^ returnString = Uri::HexEscape( testChar );
Console::WriteLine( "The hexadecimal value of '{0}' is {1}", testChar, returnString );
char testChar = 'e';
if (Uri.IsHexDigit(testChar) == true)
Console.WriteLine("'{0}' is the hexadecimal representation of {1}", testChar, Uri.FromHex(testChar));
else
Console.WriteLine("'{0}' is not a hexadecimal character", testChar);
string returnString = Uri.HexEscape(testChar);
Console.WriteLine("The hexadecimal value of '{0}' is {1}", testChar, returnString);
let testChar = 'e'
if Uri.IsHexDigit testChar then
printfn $"'{testChar}' is the hexadecimal representation of {Uri.FromHex testChar}"
else
printfn $"'{testChar}' is not a hexadecimal character"
let returnString = Uri.HexEscape testChar
printfn $"The hexadecimal value of '{testChar}' is {returnString}"
Dim testChar As Char = "e"c
If Uri.IsHexDigit(testChar) = True Then
Console.WriteLine("'{0}' is the hexadecimal representation of {1}", testChar, Uri.FromHex(testChar))
Else
Console.WriteLine("'{0}' is not a hexadecimal character", testChar)
End If
Dim returnString As String = Uri.HexEscape(testChar)
Console.WriteLine("The hexadecimal value of '{0}' is {1}", testChar, returnString)
注解
十六进制数字是 0 到 9 的数字以及字母 A-F 或 a-f。