includes

测试一排序的范围是否包含在另排序的范围包含的所有元素,元素间的订单或等效性标准可能是按二进制谓词指定。

template<class InputIterator1, class InputIterator2> 
   bool includes( 
      InputIterator1 _First1,  
      InputIterator1 _Last1, 
      InputIterator2 _First2,  
      InputIterator2 _Last1 
   ); 
template<class InputIterator1, class InputIterator2, class BinaryPredicate> 
   bool includes( 
      InputIterator1 _First1,  
      InputIterator1 _Last1, 
      InputIterator2 _First2,  
      InputIterator2 _Last1,
      BinaryPredicate _Comp 
   );

参数

  • _First1
    处理第一元素位置的输入迭代器在第一源区排序要测试的所有元素第二是在第一个中。

  • _Last1
    寻址个元素的输入迭代器位置在第一源区要测试两排序的所有元素第二是在第一个中。

  • _First2
    处理第一元素位置的输入迭代器位于第二两个连续的源区要测试的所有元素第二是在第一个中。

  • _Last2
    寻址个元素的输入迭代器位置的一个第二两个连续的源区要测试的所有元素第二是在第一个中。

  • _Comp
    用户定义的谓词函数对象定义一个元素小于另一个。 二进制谓词采用两个参数,并且在满足时返回 true,在未满足时返回 false

返回值

true,则首先排序的范围中第二个排序的范围包含任何元素;否则,false

备注

另一种观点测试是确定了第二个源范围是否为第一个源区的子集。

引用的顺序源区必须是有效的;所有指针必须 dereferenceable,因此,在每个序列中,最后位置必须是可访问的。从开始递增。

必须将每个源区排序的,当给算法的应用程序的一个前置条件包括根据的顺序相同。将算法使用顺序组合的范围。

算法不修改源区 合并

输入迭代器的值类型是小于可比较进行排序,因此,将两个元素,可以决定为它们是等效的 (从这个意义上来讲没有其他比不小于) 或一个条件比其他条件更少。 这将导致在非等效元素之间进行排序。 更确切地说,测试算法。首先排序的范围中的所有元素在指定的二进制谓词下是否存在等效于排序位于第二个排序的范围。

算法的复杂性是线性的最多 2 * ( (_Last1 – _First1) – (_Last2 – _First2) ) – 1 的非空源区的比较。

示例

// alg_includes.cpp
// compile with: /EHsc
#include <vector>
#include <algorithm>
#include <functional>      // For greater<int>( )
#include <iostream>

// Return whether modulus of elem1 is less than modulus of elem2
bool mod_lesser (int elem1, int elem2 )
{
   if ( elem1 < 0 ) 
      elem1 = - elem1;
   if ( elem2 < 0 ) 
      elem2 = - elem2;
   return elem1 < elem2;
}

int main( )
{
   using namespace std;
   vector <int> v1a, v1b;
   vector <int>::iterator Iter1a,  Iter1b;

   // Constructing vectors v1a & v1b with default less-than ordering
   int i;
   for ( i = -2 ; i <= 4 ; i++ )
   {
      v1a.push_back(  i );
   }

   int ii;
   for ( ii =-2 ; ii <= 3 ; ii++ )
   {
      v1b.push_back(  ii  );
   }

   cout << "Original vector v1a with range sorted by the\n "
        << "binary predicate less than is v1a = ( " ;
   for ( Iter1a = v1a.begin( ) ; Iter1a != v1a.end( ) ; Iter1a++ )
      cout << *Iter1a << " ";
   cout << ")." << endl;

   cout << "Original vector v1b with range sorted by the\n "
        <<  "binary predicate less than is v1b = ( " ;
   for ( Iter1b = v1b.begin ( ) ; Iter1b != v1b.end ( ) ; Iter1b++ )
      cout << *Iter1b << " ";
   cout << ")." << endl;
   
   // Constructing vectors v2a & v2b with ranges sorted by greater
   vector <int> v2a ( v1a ) , v2b ( v1b );
   vector <int>::iterator Iter2a,  Iter2b;
   sort ( v2a.begin ( ) , v2a.end ( ) , greater<int> ( ) );
   sort ( v2b.begin ( ) , v2b.end ( ) , greater<int> ( ) );
   v2a.pop_back ( );

   cout << "Original vector v2a with range sorted by the\n "
        <<  "binary predicate greater is v2a = ( " ;
   for ( Iter2a = v2a.begin ( ) ; Iter2a != v2a.end ( ) ; Iter2a++ )
      cout << *Iter2a << " ";
   cout << ")." << endl;

   cout << "Original vector v2b with range sorted by the\n "
        <<  "binary predicate greater is v2b = ( " ;
   for ( Iter2b = v2b.begin ( ) ; Iter2b != v2b.end ( ) ; Iter2b++ )
      cout << *Iter2b << " ";
   cout << ")." << endl;

   // Constructing vectors v3a & v3b with ranges sorted by mod_lesser
   vector <int> v3a ( v1a ), v3b ( v1b ) ;
   vector <int>::iterator Iter3a, Iter3b;
   reverse (v3a.begin( ), v3a.end( ) );
   v3a.pop_back ( );
   v3a.pop_back ( );
   sort ( v3a.begin ( ) , v3a.end ( ) , mod_lesser );
   sort ( v3b.begin ( ) , v3b.end ( ) , mod_lesser );

   cout << "Original vector v3a with range sorted by the\n "
        <<  "binary predicate mod_lesser is v3a = ( " ;
   for ( Iter3a = v3a.begin ( ) ; Iter3a != v3a.end ( ) ; Iter3a++ )
      cout << *Iter3a << " ";
   cout << ")." << endl;

   cout << "Original vector v3b with range sorted by the\n "
        <<  "binary predicate mod_lesser is v3b = ( " ;
   for ( Iter3b = v3b.begin ( ) ; Iter3b != v3b.end ( ) ; Iter3b++ )
      cout << *Iter3b << " ";
   cout << ")." << endl;

   // To test for inclusion under an asscending order
   // with the default binary predicate less <int> ( )
   bool Result1;
   Result1 = includes ( v1a.begin ( ) , v1a.end ( ) ,
      v1b.begin ( ) , v1b.end ( ) );
   if ( Result1 )
      cout << "All the elements in vector v1b are "
           << "contained in vector v1a." << endl;
   else
      cout << "At least one of the elements in vector v1b "
           << "is not contained in vector v1a." << endl;

   // To test for inclusion under descending
   // order specify binary predicate greater<int>( )
   bool Result2;
   Result2 = includes ( v2a.begin ( ) , v2a.end ( ) ,
      v2b.begin ( ) , v2b.end ( ) , greater <int> ( ) );
   if ( Result2 )
      cout << "All the elements in vector v2b are "
           << "contained in vector v2a." << endl;
   else
      cout << "At least one of the elements in vector v2b "
           << "is not contained in vector v2a." << endl;

   // To test for inclusion under a user
   // defined binary predicate mod_lesser
   bool Result3;
   Result3 = includes ( v3a.begin ( ) , v3a.end ( ) ,
      v3b.begin ( ) , v3b.end ( ) , mod_lesser );
   if ( Result3 )
      cout << "All the elements in vector v3b are "
           << "contained under mod_lesser in vector v3a."
           << endl;
   else
      cout << "At least one of the elements in vector v3b is "
           << " not contained under mod_lesser in vector v3a." 
           << endl;
}
  

要求

标头: <算法>

命名空间: std

请参见

参考

includes(STL 示例)

includes 的谓词版本

标准模板库