list::end
返回用于发现列表中最后一个元素之后的位置的迭代器。
const_iterator end( ) const; iterator end( );
返回值
用于发现列表中最后一个元素之后的位置的双向迭代器。 如果列表为空,则 list::end == list::begin。
备注
end 用于测试迭代器是否已到达列表的末尾。
示例
// list_end.cpp
// compile with: /EHsc
#include <list>
#include <iostream>
int main( )
{
using namespace std;
list <int> c1;
list <int>::iterator c1_Iter;
c1.push_back( 10 );
c1.push_back( 20 );
c1.push_back( 30 );
c1_Iter = c1.end( );
c1_Iter--;
cout << "The last integer of c1 is " << *c1_Iter << endl;
c1_Iter--;
*c1_Iter = 400;
cout << "The new next-to-last integer of c1 is "
<< *c1_Iter << endl;
// If a const iterator had been declared instead with the line:
// list <int>::const_iterator c1_Iter;
// an error would have resulted when inserting the 400
cout << "The list is now:";
for ( c1_Iter = c1.begin( ); c1_Iter != c1.end( ); c1_Iter++ )
cout << " " << *c1_Iter;
}
要求
标头:<list>
命名空间: std