equal
通过元素实际上比较两个值范围元素二进制等效的指定谓词或相等。
template<class InputIterator1, class InputIterator2>
bool equal(
InputIterator1 _First1,
InputIterator1 _Last1,
InputIterator2 _First2
);
template<class InputIterator1, class InputIterator2, class BinaryPredicate>
bool equal(
InputIterator1 _First1,
InputIterator1 _Last1,
InputIterator2 _First2,
BinaryPredicate _Comp
);
参数
_First1
处理第一元素位置的输入迭代器将测试的第一个范围。_Last1
寻址最终元素的输入迭代器位置一个将要测试的第一个范围。_First2
处理第一元素位置的输入迭代器将测试的第二个范围。_Comp
定义将满足的条件的用户定义的谓词函数对象,如果两个元素将采用为相等。 二进制谓词采用两个参数,并且在满足时返回 true,在未满足时返回 false。
返回值
true,如果,因此,只有值域相同或等效的二进制谓词下,当比较的元素由元素;否则,false。
备注
要搜索的范围必须是有效的;所有指针必须 dereferenceable,并且最后位置从开始来访问通过递增。
算法复杂性的时间都是线性在范围包含的元素的数目。
operator== 用于确定在元素相等必须对在其操作数之间存在着用关系。
示例
// alg_equal.cpp
// compile with: /EHsc
#include <vector>
#include <algorithm>
#include <iostream>
// Return whether second element is twice the first
bool twice ( int elem1, int elem2 )
{
return elem1 * 2 == elem2;
}
int main( )
{
using namespace std;
vector <int> v1, v2, v3;
vector <int>::iterator Iter1, Iter2, Iter3;
int i;
for ( i = 0 ; i <= 5 ; i++ )
{
v1.push_back( 5 * i );
}
int ii;
for ( ii = 0 ; ii <= 5 ; ii++ )
{
v2.push_back( 5 * ii );
}
int iii;
for ( iii = 0 ; iii <= 5 ; iii++ )
{
v3.push_back( 10 * iii );
}
cout << "v1 = ( " ;
for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter1++ )
cout << *Iter1 << " ";
cout << ")" << endl;
cout << "v2 = ( " ;
for ( Iter2 = v2.begin( ) ; Iter2 != v2.end( ) ; Iter2++ )
cout << *Iter2 << " ";
cout << ")" << endl;
cout << "v3 = ( " ;
for ( Iter3 = v3.begin( ) ; Iter3 != v3.end( ) ; Iter3++ )
cout << *Iter3 << " ";
cout << ")" << endl;
// Testing v1 and v2 for equality under identity
bool b;
b = equal( v1.begin( ), v1.end( ), v2.begin( ) );
if ( b )
cout << "The vectors v1 and v2 are equal under equality."
<< endl;
else
cout << "The vectors v1 and v2 are not equal under equality."
<< endl;
// Testing v1 and v3 for equality under identity
bool c;
c = equal( v1.begin( ), v1.end( ), v3.begin( ) );
if ( c )
cout << "The vectors v1 and v3 are equal under equality."
<< endl;
else
cout << "The vectors v1 and v3 are not equal under equality."
<< endl;
// Testing v1 and v3 for equality under twice
bool d;
d = equal( v1.begin( ), v1.end( ), v3.begin( ), twice );
if ( d )
cout << "The vectors v1 and v3 are equal under twice."
<< endl;
else
cout << "The vectors v1 and v3 are not equal under twice."
<< endl;
}
要求
标头: <算法>
命名空间: std