prev_permutation

重新排序的范围中的原始元素，以便按照字典将以前更大的范围替换，如果该文件存在，其中有意义以前指定能具有二进制谓词。

template<class BidirectionalIterator>
   bool prev_permutation(
      BidirectionalIterator _First, 
      BidirectionalIterator _Last
   );
template<class BidirectionalIterator, class BinaryPredicate>
   bool prev_permutation(
      BidirectionalIterator _First, 
      BidirectionalIterator _Last,
      BinaryPredicate _Comp
   );

参数

• _First
  指向第一元素的位置的双向迭代器将交换的范围。

• _Last
  指向在最终元素的位置的一双向迭代器将交换的范围。

• _Comp
  定义的顺序连续的元素将满足的比较条件的用户定义的谓词函数对象。 binary 谓词采用两个参数并返回 true，在满足和 false，当没有足够。

返回值

true 字典的范围，则以前存在和替换原始顺序范围；false，否则，在订单转换到字典进行最大范围的情况下。

备注

引用的范围必须是有效的；所有指针必须 dereferenceable，然后在序列中的最后位置从开始来访问通过递增。

默认二进制谓词比并在范围的元素必须小于可比较确保小于的排列是显式定义的。

复杂是线性的，且至少 ( _Last - _First)/2 张交换。

示例

// alg_prev_perm.cpp
// compile with: /EHsc
#include <vector>
#include <deque>
#include <algorithm>
#include <iostream>
#include <ostream>

using namespace std;
class CInt;
ostream& operator<<( ostream& osIn, const CInt& rhs );

class CInt {
public:
   CInt( int n = 0 ) : m_nVal( n ){}
   CInt( const CInt& rhs ) : m_nVal( rhs.m_nVal ){}
   CInt&   operator=( const CInt& rhs ) {m_nVal =
   rhs.m_nVal; return *this;}
   bool operator<( const CInt& rhs ) const
      {return ( m_nVal < rhs.m_nVal );}
   friend ostream& operator<<( ostream& osIn, const CInt& rhs );

private:
   int m_nVal;
};

inline ostream& operator<<( ostream& osIn, const CInt& rhs ) {
   osIn << "CInt( " << rhs.m_nVal << " )";
   return osIn;
}

// Return whether modulus of elem1 is less than modulus of elem2
bool mod_lesser (int elem1, int elem2 ) {
   if ( elem1 < 0 )
      elem1 = - elem1;
   if ( elem2 < 0 )
      elem2 = - elem2;
   return elem1 < elem2;
};

int main() {
   // Reordering the elements of type CInt in a deque
   // using the prev_permutation algorithm
   CInt c1 = 1, c2 = 5, c3 = 10;
   bool deq1Result;
   deque<CInt> deq1, deq2, deq3;
   deque<CInt>::iterator d1_Iter;

   deq1.push_back ( c1 );
   deq1.push_back ( c2 );
   deq1.push_back ( c3 );

   cout << "The original deque of CInts is deq1 = (";
   for ( d1_Iter = deq1.begin( ); d1_Iter != --deq1.end( ); d1_Iter++ )
      cout << " " << *d1_Iter << ",";
   d1_Iter = --deq1.end( );
   cout << " " << *d1_Iter << " )." << endl;

   deq1Result = prev_permutation ( deq1.begin ( ) , deq1.end ( ) );

   if ( deq1Result )
      cout << "The lexicographically previous permutation "
           << "exists and has \nreplaced the original "
           << "ordering of the sequence in deq1." << endl;
   else
      cout << "The lexicographically previous permutation doesn't "
           << "exist\n and the lexicographically "
           << "smallest permutation\n has replaced the "
           << "original ordering of the sequence in deq1." << endl;

   cout << "After one application of prev_permutation,\n deq1 = (";
   for ( d1_Iter = deq1.begin( ); d1_Iter != --deq1.end( ); d1_Iter++ )
      cout << " " << *d1_Iter << ",";
   d1_Iter = --deq1.end( );
   cout << " " << *d1_Iter << " )." << endl << endl;

   // Permutating vector elements with binary function mod_lesser
   vector <int> v1;
   vector <int>::iterator Iter1;

   int i;
   for ( i = -3 ; i <= 3 ; i++ )
      v1.push_back( i );

   cout << "Vector v1 is ( " ;
   for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter1++ )
      cout << *Iter1 << " ";
   cout << ")." << endl;

   prev_permutation ( v1.begin ( ) , v1.end ( ) , mod_lesser );

   cout << "After the first prev_permutation, vector v1 is:\n v1 = ( " ;
   for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ; Iter1++ )
      cout << *Iter1 << " ";
   cout << ")." << endl;

   int iii = 1;
   while ( iii <= 5 ) {
      prev_permutation ( v1.begin ( ) , v1.end ( ) , mod_lesser );
      cout << "After another prev_permutation of vector v1,\n v1 =   ( " ;
      for ( Iter1 = v1.begin( ) ; Iter1 != v1.end( ) ;Iter1 ++ )
         cout << *Iter1  << " ";
      cout << ")." << endl;
      iii++;
   }
}

要求

标头： <算法>

命名空间: std

请参见

参考

prev_permutation（STL 示例）

标准模板库