GROUPPARTITION (Entity SQL)
返回从聚合与之相关的当前组分区提取的参数值集合。 GroupPartition 聚合是基于组的聚合,没有基于集合的形式。
GROUPPARTITION( [ALL|DISTINCT] expression )
参数
- expression
任何 Entity SQL 表达式。
备注
以下查询生成产品列表以及每个产品的订单行数量的集合。
select p, GroupPartition(ol.Quantity) from LOB.OrderLines as ol
group by ol.Product as p
以下两个查询在语义上是相同的:
select p, Sum(GroupPartition(ol.Quantity)) from LOB.OrderLines as ol
group by ol.Product as p
select p, Sum(ol.Quantity) from LOB.OrderLines as ol
group by ol.Product as p
GROUPPARTITION 运算符可以与用户定义的聚合函数结合使用。
GROUPPARTITION 是一个特殊的聚合运算符,它保留对于分组的输入集的引用。 此引用可以用在 GROUP BY 处于作用域内的查询中的任何位置。 例如:
select p, GroupPartition(ol.Quantity) from LOB.OrderLines as ol group by ol.Product as p
使用正则 GROUP BY,分组的结果处于隐藏状态。 您只能在聚合函数中使用结果。 为了能够看到分组的结果,必须使用子查询使分组的结果与输入集相关。 下面两个查询是等效的:
select p, (select q from GroupPartition(ol.Quantity) as q) from LOB.OrderLines as ol group by ol.Product as p
select p, (select ol.Quantity as q from LOB.OrderLines as ol2 where ol2.Product = p) from LOB.OrderLines as ol group by ol.Product as p
如示例中所示,通过 GROUPPARTITION 聚合运算符,可以在分组后更轻松地获得对输入集的引用。
当您使用 expression 参数时,GROUPPARTITION 运算符可以在运算符输入中指定任何 Entity SQL 表达式。
例如,下面针对组分区的所有输入表达式都是有效的:
select groupkey, GroupPartition(b) from {1,2,3} as a inner join {4,5,6} as b on true group by a as groupkey
select groupkey, GroupPartition(1) from {1,2,3} as a inner join {4,5,6} as b on true group by a as groupkey
select groupkey, GroupPartition(a + b) from {1,2,3} as a inner join {4,5,6} as b on true group by a as groupkey
select groupkey, GroupPartition({a + b}) from {1,2,3} as a inner join {4,5,6} as b on true group by a as groupkey
select groupkey, GroupPartition({42}) from {1,2,3} as a inner join {4,5,6} as b on true group by a as groupkey
select groupkey, GroupPartition(b > a) from {1,2,3} as a inner join {4,5,6} as b on true group by a as groupkey
示例
下面的示例演示如何将 GROUPPARTITION 子句与 GROUP BY 子句一起使用。 GROUP BY 子句按照 SalesOrderHeader
实体的 Contact
对这些实体进行分组。 然后,GROUPPARTITION 子句投影每个组的 TotalDue
属性,而生成一个十进制值集合。
USING Microsoft.Samples.Entity
Function MyAvg(dues Collection(Decimal)) AS
(
Avg(select value due from dues as due where due > @price)
)
SELECT TOP(10) contactID, MyAvg(GroupPartition(order.TotalDue))
FROM AdventureWorksEntities.SalesOrderHeaders AS order
GROUP BY order.Contact.ContactID as contactID;