negative_binomial_distribution 类
生成负二项式分布。
template<class IntType = int> class negative_binomial_distribution { public: // types typedef IntType result_type; struct param_type; // constructor and reset functions explicit negative_binomial_distribution(IntType k = 1, double p = 0.5); explicit negative_binomial_distribution(const param_type& parm); void reset(); // generating functions template<class URNG> result_type operator()(URNG& gen); template<class URNG> result_type operator()(URNG& gen, const param_type& parm); // property functions IntType k() const; double p() const; param_type param() const; void param(const param_type& parm); result_type min() const; result_type max() const; };
参数
- IntType
整数结果类型,默认为 int。 有关可能的类型,请参阅 <random>。
备注
如果未根据负二项式分布离散型概率函数提供和分布任何类型,则模板类将描述产生用户指定的整型值或 int 型值的分布。 下表链接到有关各个成员的文章。
negative_binomial_distribution::negative_binomial_distribution |
negative_binomial_distribution::k |
negative_binomial_distribution::param |
negative_binomial_distribution::operator() |
negative_binomial_distribution::p |
属性成员 k() 和 p() 将分别返回当前存储的分布参数值 k 和 p。
有关分布类及其成员的详细信息,请参阅 <random>。
有关负二项式分布离散型概率函数的详细信息,请参阅 Wolfram MathWorld 文章负二项式分布。
示例
// compile with: /EHsc /W4
#include <random>
#include <iostream>
#include <iomanip>
#include <string>
#include <map>
void test(const int k, const double p, const int& s) {
// uncomment to use a non-deterministic seed
// std::random_device rd;
// std::mt19937 gen(rd());
std::mt19937 gen(1729);
std::negative_binomial_distribution<> distr(k, p);
std::cout << std::endl;
std::cout << "k == " << distr.k() << std::endl;
std::cout << "p == " << distr.p() << std::endl;
// generate the distribution as a histogram
std::map<int, int> histogram;
for (int i = 0; i < s; ++i) {
++histogram[distr(gen)];
}
// print results
std::cout << "Histogram for " << s << " samples:" << std::endl;
for (const auto& elem : histogram) {
std::cout << std::setw(5) << elem.first << ' ' << std::string(elem.second, ':') << std::endl;
}
std::cout << std::endl;
}
int main()
{
int k_dist = 1;
double p_dist = 0.5;
int samples = 100;
std::cout << "Use CTRL-Z to bypass data entry and run using default values." << std::endl;
std::cout << "Enter an integer value for k distribution (where 0 < k): ";
std::cin >> k_dist;
std::cout << "Enter a double value for p distribution (where 0.0 < p <= 1.0): ";
std::cin >> p_dist;
std::cout << "Enter an integer value for a sample count: ";
std::cin >> samples;
test(k_dist, p_dist, samples);
}
输出
首次运行:
Use CTRL-Z to bypass data entry and run using default values.
Enter an integer value for k distribution (where 0 < k): 1
Enter a double value for p distribution (where 0.0 < p <= 1.0): .5
Enter an integer value for a sample count: 100
k == 1
p == 0.5
Histogram for 100 samples:
0 :::::::::::::::::::::::::::::::::::::::::::
1 ::::::::::::::::::::::::::::::::
2 ::::::::::::
3 :::::::
4 ::::
5 ::
第二次运行:
Use CTRL-Z to bypass data entry and run using default values.
Enter an integer value for k distribution (where 0 < k): 100
Enter a double value for p distribution (where 0.0 < p <= 1.0): .667
Enter an integer value for a sample count: 100
k == 100
p == 0.667
Histogram for 100 samples:
31 ::
32 :
33 ::
34 :
35 ::
37 ::
38 :
39 :
40 ::
41 :::
42 :::
43 :::::
44 :::::
45 ::::
46 ::::::
47 ::::::::
48 :::
49 :::
50 :::::::::
51 :::::::
52 ::
53 :::
54 :::::
56 ::::
58 :
59 :::::
60 ::
61 :
62 ::
64 :
69 ::::
要求
标头:<random>
命名空间: std