通过

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Grant 方法 (ObjectPermissionSet, String, String[])

针对表的指定列的指定被授权者，授予对指定列的指定权限的访问。

命名空间：  Microsoft.SqlServer.Management.Smo
程序集：  Microsoft.SqlServer.Smo（在 Microsoft.SqlServer.Smo.dll 中）

语法

声明
Public Sub Grant ( _
    permission As ObjectPermissionSet, _
    granteeName As String, _
    columnNames As String() _
)
用法
Dim instance As Table
Dim permission As ObjectPermissionSet
Dim granteeName As String
Dim columnNames As String()

instance.Grant(permission, granteeName, _
    columnNames)

public void Grant(
    ObjectPermissionSet permission,
    string granteeName,
    string[] columnNames
)

public:
virtual void Grant(
    ObjectPermissionSet^ permission, 
    String^ granteeName, 
    array<String^>^ columnNames
) sealed

abstract Grant : 
        permission:ObjectPermissionSet * 
        granteeName:string * 
        columnNames:string[] -> unit 
override Grant : 
        permission:ObjectPermissionSet * 
        granteeName:string * 
        columnNames:string[] -> unit 

public final function Grant(
    permission : ObjectPermissionSet, 
    granteeName : String, 
    columnNames : String[]
)

参数

  • columnNames
    类型：array<System. . :: . .String> [] () [] []
    一个 String 数组值，该值指定要向其授予权限集的列的列表。

实现

IColumnPermission. . :: . .Grant(ObjectPermissionSet, String, array<String> [] () [] [])

示例

The following code example shows how to grant a grantee account permission to select table elements of the second table column. The grantee account is a placeholder for any defined user accounts.

The following database schema is used for this snippet.

//CREATE DATABASE MYTESTDB;
//GO

//USE MYTESTDB;
//GO

//CREATE TABLE TABLE1(
//    id int,
//    name varchar(32)
//);
//GO

C#

Server srv = new Server("(local)");
Database db = srv.Databases["MYTESTDB"];

Table tb = db.Tables[0];
String[] col = new String[1];
col[0] = tb.Columns[0].Name;
col[1] = tb.Columns[1].Name

ObjectPermissionSet objPermissionSet = new ObjectPermissionSet(ObjectPermission.Select);
objPermissionSet.Select = true;
tb.Grant(objPermissionSet, grantee, col[]);

Powershell

$srv = new-Object Microsoft.SqlServer.Management.Smo.Server("(local)")
$db = New-Object Microsoft.SqlServer.Management.Smo.Database
$db = $srv.Databases.Item("MYTESTDB")
$tb = $db.Tables[0]
$col = @($tb.Columns[0].Name, $tb.Columns[1].Name)

$objPermissionSet = new-object Microsoft.SqlServer.Management.Smo.ObjectPermissionSet([Microsoft.SqlServer.Management.Smo.ObjectPermission]::Select)
$objPermissionSet.Select = $TRUE
$tb.Grant($objPermissionSet, grantee, $col)